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Advocard [28]
3 years ago
15

Let f(x)=e^x and g(x)=x-3 what are the domain and range of (f g) (x)

Mathematics
2 answers:
inysia [295]3 years ago
5 0

Answer:

D. Domain: all rea numbers

Range: y >0

Step-by-step explanation:

Let f(x) =e^x

Domain of function f(x) : all real numbers because it is define for every real number.

Range of function f(x) y >0 because exponential function can never  be zero.

g(x)=x-3

Domain of g(x) : all real numbers

Range g(x): all real numbers.

(fg)(x)= f(g(x))

f(x-3)=e^{x-3}

(fg)(x)= e^{x-3}

Put x=0  then we get

(fg)(0)= [tex]e^{0-3}

(fg)(0)=e^{-3}

Domain of (fg)(x) is the set of real numbers because it is define for every real number.

Exponential function can never be zero .

Function (fg)(x) can never be zero it is always greater than zero because it is an exponential function

Therefore , the range of (fg)(x) is greater than zero.

Hence, option D  is correct .

Domain: all real numbers

Range: y >0

Brrunno [24]3 years ago
3 0
The domain and range of g are "all real numbers," so you want to find the range of f when its argument is from the set "all real numbers." That range is y > 0. The appropriate choice is
  D. domain: all real numbers; range: y > 0
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+2 |   +1     0     -1     0     0     -5

    |<u>                                              </u>

Next you bring down the first coefficient:

+2 |   +1     0     -1     0     0     -5

    |<u>                                              </u>

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Then you multiply it by the divisor and write the product under the next coefficient:

+2 |   +1     0     -1     0     0     -5

    |<u>           +2                                   </u>

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Next add the column and put the sum below it:

+2 |   +1     0     -1     0     0     -5

    |<u>          +2                                   </u>

        +1    +2

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+2 |   +1     0     -1     0     0     -5

    |<u>          +2    +4   +6   +12   +24 </u>

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Now the last coefficient is your remainder. So your results will be:

x⁴+2x³ +3x²+6x +12 r. \dfrac{19}{x-2}

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