Given:
The parallel sides of a trapezium are 28.7 cm and 22.3 cm.
The distance between parallel sides is 16 cm.
To find:
The area of a trapezium.
Solution:
The area of the trapezium is:
Where, are parallel sides and
is the vertical distance between the parallel sides.
Putting in the above formula, we get
Therefore, the area of the trapezium is 408 square cm.
Answer:
65°
Step-by-step explanation:
Radii CA and CB are perpendicular to tangent lines AT and BT, so
Since angle BAT is equal to 65°, angle CAB has measure
Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus
The sum of the measures of all interior angles in triangle is always 180°, so
Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so
