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Masja [62]
3 years ago
11

You run a small network for your business that has a single router connected to the Internet and a single switch. You keep sensi

tive documents on a computer that you would like to keep isolated from other computers on the network. Other hosts on the network should not be able to communicate with this computer through the switch, but you still need to access the network through the computer.
What should you use for this situation?
Computers and Technology
1 answer:
slava [35]3 years ago
3 0

Answer: VLAN

Explanation: VLAN(Virtual local area network) is the network technology that lets the user to connect in a virtual( fake) environment and displaying as if they are working in the LAN environment.

It is the used for obtaining the scalability and protection of information while communication. It also helps in adapting the change that occurs in the network and  nodes of the server. Thus, VLAN is the network that should be used in the business to keep sensitive data secure and hosts of the network to connect and communicate .

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In summary, McKibben argues that the inhabitable planet is shrinking because (select all that apply):
Artist 52 [7]

MCKibben argues that the inhabitable planet is shrinking because:

  • Consistently higher temperatures will likely make certain areas uninhabitable
  • Desertification will reduce the amount of harvestable land
  • Coastlines are being lost to sea level rise.

<h3>What is Shrinking?</h3>

This is the process in which an object or place becomes smaller as a result of various activities.

The most suitable options which explains why the planet is shrinking is as a result of a reduction in the areas in which humans can live as a result of the factors mentioned above.

Read more about Planet here brainly.com/question/11157969

7 0
2 years ago
An administrator is writing into a database and received an error detailed in the exhibit. What two steps need to be taken to re
d1i1m1o1n [39]

An administrator is writing into a database and received an error detailed in the exhibit. The two steps to be taken to resolve this are :

Move the Execute SQL statement to be between Connect and Disconnect. Move the Prompt Message to be before the Disconnect statements.

Explanation:

  • Dynamic SQL refers to SQL statements that are generated at run-time.
  • To disconnect from a database, in the Database Navigator or Projects view, click the connection and then click the Disconnect button in the toolbar or click Database -> Disconnect on the main menu
  • You can also right-click the connection and click Disconnect on the context menu
  • The PROMPT command may be used to display messages to the user, perhaps supplying a short summary of what your script is going to accomplish.
  • The SQL EXECUTE command executes an SQL command and binds the result to 4D objects (arrays, variables or fields).
  • A valid connection must be specified in the current process in order to execute this command. The sqlStatement parameter contains the SQL command to execute.

7 0
3 years ago
Given parameters b and h which stand for the base and the height of an isosceles triangle (i.e., a triangle that has two equal s
schepotkina [342]

Answer:

The area of the triangle is calculated as thus:

Area = 0.5 * b * h

To calculate the perimeter of the triangle, the measurement of the slant height has to be derived;

Let s represent the slant height;

Dividing the triangle into 2 gives a right angled triangle;

The slant height, s is calculated using Pythagoras theorem as thus

s = \sqrt{b^2 + h^2}

The perimeter of the triangle is then calculated as thus;

Perimeter = s + s + b

Perimeter = \sqrt{b^2 + h^2} + \sqrt{b^2 + h^2} +b

Perimeter = 2\sqrt{b^2 + h^2} + b

For the volume of the cone,

when the triangle is spin, the base of the triangle forms the diameter of the cone;

Volume = \frac{1}{3} \pi * r^2 * h

Where r = \frac{1}{2} * diameter

So, r = \frac{1}{2}b

So, Volume = \frac{1}{3} \pi * (\frac{b}{2})^2 * h

Base on the above illustrations, the program is as follows;

#include<iostream>

#include<cmath>

using namespace std;

void CalcArea(double b, double h)

{

//Calculate Area

double Area = 0.5 * b * h;

//Print Area

cout<<"Area = "<<Area<<endl;

}

void CalcPerimeter(double b, double h)

{

//Calculate Perimeter

double Perimeter = 2 * sqrt(pow(h,2)+pow((0.5 * b),2)) + b;

//Print Perimeter

cout<<"Perimeter = "<<Perimeter<<endl;

}

void CalcVolume(double b, double h)

{

//Calculate Volume

double Volume = (1.0/3.0) * (22.0/7.0) * pow((0.5 * b),2) * h;

//Print Volume

cout<<"Volume = "<<Volume<<endl;

}

int main()

{

double b, h;

//Prompt User for input

cout<<"Base: ";

cin>>b;

cout<<"Height: ";

cin>>h;

//Call CalcVolume function

CalcVolume(b,h);

//Call CalcArea function

CalcArea(b,h);

//Call CalcPerimeter function

CalcPerimeter(b,h);

 

return 0;

}

3 0
3 years ago
10. Question<br> What are the drawbacks of purchasing something online? Check all that apply.
max2010maxim [7]

Explanation:

1) the quality of purchased good may be low

2) there might me fraud and cheaters

3) it might be risky

4) we may not get our orders on time

7 0
2 years ago
Write a python program to read four numbers (representing the four octets of an IP) and print the next five IP addresses. Be sur
sdas [7]

Answer:

first_octet = int(input("Enter the first octet: "))

second_octet = int(input("Enter the second octet: "))

third_octet = int(input("Enter the third octet: "))

forth_octet = int(input("Enter the forth octet: "))

octet_start = forth_octet + 1

octet_end = forth_octet + 6

if (1 <= first_octet <= 255) and (0 <= second_octet <= 255) and (0 <= third_octet <= 255) and (0 <= forth_octet <= 255):

   for ip in range(octet_start, octet_end):

       forth_octet = forth_octet + 1

       if forth_octet > 255:

           forth_octet = (forth_octet % 255) - 1

           third_octet = third_octet + 1

           if third_octet > 255:

               third_octet = (third_octet % 255) - 1

               second_octet = second_octet + 1

               if second_octet > 255:

                   second_octet = (second_octet % 255) - 1

                   first_octet = first_octet + 1

                   if first_octet > 255:

                       print("No more available IP!")

                       break

       print(str(first_octet) + "." + str(second_octet) + "." + str(third_octet) + "." + str(forth_octet))

else:

   print("Invalid input!")

Explanation:

- Ask the user for the octets

- Initialize the start and end points of the loop, since we will be printing next 5 IP range is set accordingly

- Check if the octets meet the restrictions

- Inside the loop, increase the forth octet by 1 on each iteration

- Check if octets reach the limit - 255, if they are greater than 255, calculate the mod and subtract 1. Then increase the previous octet by 1.

For example, if the input is: 1. 1. 20. 255, next ones will be:

1. 1. 21. 0

1. 1. 21. 1

1. 1. 21. 2

1. 1. 21. 3

1. 1. 21. 4

There is an exception for the first octet, if it reaches 255 and others also reach 255, this means there are no IP available.

- Print the result

8 0
3 years ago
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