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Masja [62]
3 years ago
11

You run a small network for your business that has a single router connected to the Internet and a single switch. You keep sensi

tive documents on a computer that you would like to keep isolated from other computers on the network. Other hosts on the network should not be able to communicate with this computer through the switch, but you still need to access the network through the computer.
What should you use for this situation?
Computers and Technology
1 answer:
slava [35]3 years ago
3 0

Answer: VLAN

Explanation: VLAN(Virtual local area network) is the network technology that lets the user to connect in a virtual( fake) environment and displaying as if they are working in the LAN environment.

It is the used for obtaining the scalability and protection of information while communication. It also helps in adapting the change that occurs in the network and  nodes of the server. Thus, VLAN is the network that should be used in the business to keep sensitive data secure and hosts of the network to connect and communicate .

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wariber [46]
Antivirus software, or anti-virus software, also known as anti-malware, is a computer program used to prevent, detect, and remove malware. Antivirus software was originally developed to detect and remove computer viruses, hence the name.
8 0
3 years ago
Read 2 more answers
To achieve the maximum confidentiality and integrity found in a completely secure information system would require that the syst
fgiga [73]

Answer:

The answer is "Option a".

Explanation:

Privacy is a set of rules, which limiting access to the data, and integrity ensures impartiality, accuracy, and reliability is assured to ensure, which authorized persons can have secure access to the data.

The system needs no access for everyone to achieve its secrecy and integrity contained in a completely safe data system, that's why the given statement is "true".

5 0
3 years ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
For this problem, you will write a function standard_deviation that takes a list whose elements are numbers (they may be floats
Evgesh-ka [11]

Answer:

  1. import math  
  2. def standard_deviation(aList):
  3.    sum = 0
  4.    for x in aList:
  5.        sum += x  
  6.    
  7.    mean = sum / float(len(aList))
  8.    sumDe = 0
  9.    for x in aList:
  10.        sumDe += (x - mean) * (x - mean)
  11.    
  12.    variance = sumDe / float(len(aList))
  13.    SD = math.sqrt(variance)
  14.    return SD  
  15. print(standard_deviation([3,6, 7, 9, 12, 17]))

Explanation:

The solution code is written in Python 3.

Firstly, we need to import math module (Line 1).

Next, create a function standard_deviation that takes one input parameter, which is a list (Line 3). In the function, calculate the mean for the value in the input list (Line 4-8). Next, use the mean to calculate the variance (Line 10-15). Next, use sqrt method from math module to get the square root of variance and this will result in standard deviation (Line 16). At last, return the standard deviation (Line 18).

We can test the function using a sample list (Line 20) and we shall get 4.509249752822894

If we pass an empty list, a ZeroDivisionError exception will be raised.

3 0
3 years ago
JAVA Code:
Burka [1]
Dear ,you should ask it on stackoverflow and geekforgeelks , not here
6 0
4 years ago
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