Answer:
Explanation:
The following Python code is a function that takes in an array as a parameter, it then loops through the array determining if the element is divisible by 3. If it is it leaves it alone, otherwise it changes it to a 0. Then ouputs the array. A test case is shown in the attached image below using a sample array.
def divisible_by_three(array):
for x in array:
if x % 3 == 0:
pass
else:
array[array.index(x)] = 0
return array
Answer:
a. Radom Access Memory (RAM).
Explanation:
If a computer user modifies a document that is saved on his or her computer. This changes are stored on the Radom Access Memory (RAM) until the computer user save the document.
Radom Access Memory (RAM) can be defined as the main memory of a computer system which allow users to store commands and data temporarily.
Generally, the Radom Access Memory (RAM) is a volatile memory and as such can only retain data temporarily.
All software applications temporarily stores and retrieves data from a Radom Access Memory (RAM) in computer, this is to ensure that informations are quickly accessible, therefore it supports read and write of files.
Answer:
"Router screening" is the correct option.
Explanation:
- A router that philters packets like a firewall. For certain instances, the whole firewall system is such a single scanning router.
- Often connected to a network stage as well as a container-filter firewall has been the scanning router firewall. This rather firewall operates by filtering protocol characteristics from received packets.
So that the above seems to be the correct approach.
Hexadecimal numbers are just a convenient representation of binary data. When entered as text, they consist of ASCII characters 0-9 and a-f. The numbers will then have to be converted to binary. This is accomplished by converting to uppercase, subtracting the ASCII offset (48 for 0-9 or 55 for A-F), so that the result is a number between 0 and 15 (inclusive). This can be stored in computer memory to represent 4 bits.
Hexadecimal numbers represent binary numbers in the following way:
hex | binary
0 = 0000
1 = 0001
2 = 0010
3 = 0011
4 = 0100
5 = 0101
6 = 0110
7 = 0111
8 = 1000
9 = 1001
a = 1010
b = 1011
c = 1100
d = 1101
e = 1110
f = 1111
As you can see, no other 4 bit combination exists.
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Hope I Helped
