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Aleonysh [2.5K]

4 years ago

9

Describe how you would compare 3.6 and

rt{12} " alt=" \sqrt{12} " align="absmiddle" class="latex-formula">

2 answers:

Ostrovityanka [42]4 years ago

8 0

Answer:

Step-by-step explanation:

How can I write it

pogonyaev4 years ago

5 0

Step-by-step explanation:

√12=

2√3

÷2. ÷2

√3. 1.8

√3≈1.7

1.7<1.8

3.6>√12

method 2

(3.6)^2>12

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$\huge\boxed{\$64}$

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