Question

Describe how you would compare 3.6 and rt{12} " alt=" \sqrt{12} " align="absmiddle" class="latex-formula">
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Answer 1

Answer:

Step-by-step explanation:

How can I write it

Answer 2

Step-by-step explanation:

√12=

2√3

÷2. ÷2

√3. 1.8

√3≈1.7

1.7<1.8

3.6>√12

method 2

(3.6)^2>12