Favorite song smh I have to type 20 characters
2 answers:
You might be interested in
Answer:
<u>AP = 13</u>
Step-by-step explanation:
See the attached figure.
CD = 10 and XY = 24
Line XY bisects and is perpendicular to AB and CD
∴ XY bisects at Y
∴ CY = 0.5 CD = 0.5 * 10 = 5
And from the geometry of the shape
P is the midpoint of XY
∴ XP = YP = 0.5 XY = 0.5 * 24 = 12
XY is perpendicular to CD
∴ ΔPYC is a right triangle at Y
∴ PC (hypotenuse) =
From the figure AP = PC = 13
Answer:
(a) P (Y = 3) = 0.0844, P (Y ≤ 3) = 0.8780
(b) The probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.
Step-by-step explanation:
The random variable <em>Y</em> is defined as the number of consecutive time intervals in which the water supply remains below a critical value <em>y₀</em>.
The random variable <em>Y</em> follows a Geometric distribution with parameter <em>p</em> = 0.409<em>.</em>
The probability mass function of a Geometric distribution is:
(a)
Compute the probability that a drought lasts exactly 3 intervals as follows:
Thus, the probability that a drought lasts exactly 3 intervals is 0.0844.
Compute the probability that a drought lasts at most 3 intervals as follows:
P (Y ≤ 3) = P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3)
Thus, the probability that a drought lasts at most 3 intervals is 0.8780.
(b)
Compute the mean of the random variable <em>Y</em> as follows:
Compute the standard deviation of the random variable <em>Y</em> as follows:
The probability that the length of a drought exceeds its mean value by at least one standard deviation is:
P (Y ≥ μ + σ) = P (Y ≥ 1.445 + 1.88)
= P (Y ≥ 3.325)
= P (Y ≥ 3)
= 1 - P (Y < 3)
= 1 - P (X = 0) - P (X = 1) - P (X = 2)
Thus, the probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.