All categories

3 years ago

Solve the following: 3x+2= 2x+13/3

Mathematics

2 answers:

ivanzaharov [21]3 years ago

8 0

Answer:

x = 7/3

Step-by-step explanation:

3x + 2 = 2x + 13/3

3x - 2x = 13/3 - 2

x = 13/3 - 2/1

x = 13/3 - 6/3

x = 7/3

NISA [10]3 years ago

6 0

Answer:

x = 7/3

Step-by-step explanation:

3x + 2 = 2x + 13/3

3x - 2x = 13/3 - 2

x = 13/3 - 2/1

x = 13/3 - 6/3

x = 7/3

You might be interested in

A ramp leading into a building makes a 15 degree angle with the ground. The end of the ramp is 10 feet from the base of the buil

stiks02 [169]

Answer:

The length of the ramp is x = AC = 10.35 feet

Step-by-step explanation:

From the ΔABC

AC = x = length of ramp

BC = 10 feet

$\theta = 15$ °

$\cos 15 = \frac{BC}{AC}$

$\cos 15 = \frac{10}{x}$

x = 10.35 feet

Therefore the length of the ramp is x = AC = 10.35 feet

5 0

4 years ago

26. Define a relation ∼ ∼ on R 2 R2 by stating that ( a , b ) ∼ ( c , d ) (a,b)∼(c,d) if and only if a 2 + b 2 ≤ c 2 + d 2 . a2+

Tresset [83]

Answer:

~ is reflexive.

~ is asymmetric.

~ is transitive.

Step-by-step explanation:

~ is reflexive:

i.e., to prove $\forall (a, b) \in \mathbb{R}^2$ , $(a, b) R(a, b)$ .

That is, every element in the domain is related to itself.

The given relation is $\sim: (a,b) \sim (c, d) \iff a^2 + b^2 \leq c^2 + d^2$

Reflexive:

$(a, b) \sim (a, b)$ since $a^2 + b^2 = a^2 + b^2$

This is true for any pair of numbers in $\mathbb{R}^2$ . So, $\sim$ is reflexive.

Symmetry:

$\sim$ is symmetry iff whenever $(a, b) \sim (c, d)$ then $(c, d) \sim (a, b)$ .

Consider the following counter - example.

Let (a, b) = (2, 3) and (c, d) = (6, 3)

$a^2 + b^2 = 2^2 + 3^2 = 4 + 9 = 13$

$c^2 + d^2 = 6^2 + 3^2 = 36 + 9 = 42$

Hence, $(a, b) \sim (c, d)$ since $a^2 + b^2 \leq c^2 + d^2$

Note that $c^2 + d^2 \nleq a^2 + b^2$

Hence, the given relation is not symmetric.

Transitive:

$\sim$ is transitive iff whenever $(a, b) \sim (c, d) \hspace{2mm} \& \hspace{2mm} (c, d) \sim (e, f)$ then $(a, b) \sim (e, f)$

To prove transitivity let us assume $(a, b) \sim (c, d)$ and $(c, d) \sim (e, f)$ .

We have to show $(a, b) \sim (e, f)$

Since $(a, b) \sim (c, d)$ we have: $a^2 + b^2 \leq c^2 + d^2$

Since $(c, d) \sim (e, f)$ we have: $c^2 + d^2 \leq e^2 + f^2$

Combining both the inequalities we get:

$a^2 + b^2 \leq c^2 + d^2 \leq e^2 + f^2$

Therefore, we get: $a^2 + b^2 \leq e^2 + f^2$

Therefore, $\sim$ is transitive.

Hence, proved.

3 0

3 years ago

How do you describe the slope of a line . then find the slope

yawa3891 [41]

Here are some very good video that explain how. very short and easy too. http://virtualnerd.com/pre-algebra/linear-functions-graphing/rate-of-change-slope/finding-slope/slop... math antics on youtube is great for help too

5 0

4 years ago

Read 2 more answers

A car travels 8 miles in 12 minutes. What is the cars rate in miles per hour

lorasvet [3.4K]

60/12=5. We use the number 60 because60 minutes per hour, 8x5=40. 40mph

6 0

3 years ago

Find the length of side c in abc to the nearest tenth if b=15 degrees, c=65 degrees and a=19

fredd [130]

17 because the route

8 0

4 years ago