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PSYCHO15rus [73]
3 years ago
8

Hoodies were on sale for 20% off of the original price. Hyde bought a hoodie on sale that had an original price of $74.00. The s

ales tax was then 6.25%. How much did Hyde pay for the sweater?
Mathematics
2 answers:
AnnyKZ [126]3 years ago
7 0
74 x .2 = 14.80 thats the discount
74 - 14.80 = 59.20
59.20 x .0625 =3.7 (thats the tax, add it)
59.20 + 3.7 = 62.90 the final price
Georgia [21]3 years ago
4 0
20% off means u r paying 80%

0.80(74) = 59.20 (without tax)

sales tax is 6.25%...
59.20 + 0.0625(59.20) = 59.20 + 3.70 = $ 62.90 <==with tax included
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397.61m

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A = 1

4πd^2 = 1

4 x π x 22.52 = 397.60782

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The scale factor would be 3.5
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What is x^2 times 4x
Flura [38]
Say x is 1 1^2=1  4x=4 4*1=4  I believe that is what you were asking

6 0
4 years ago
Kayla has 18 bottles of bubbles. She wants to give 2 bottles to each of her 6 friends. How many bottles will she have left over?
MatroZZZ [7]

Answer: she would have 6 bottles left, (18/2)/6

Step-by-step explanation:

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8 0
2 years ago
Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f
tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :-  f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x)  to have a maximum or minimum at given point.

ii)  find first derivative f^{l} (x) and equating zero

iii) solve and find 'x' values

iv) Find second derivative f^{ll}(x) >0 then find the minimum value at x=a

v) Find second derivative f^{ll}(x) then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

<u>step1:</u>- find first derivative f^{l} (x) and equating zero

  f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)

f^{l}(x) = \frac{1}{x^2+1} (2x)  ……………(1)

f^{l}(x) = \frac{1}{x^2+1} (2x)=0

the point is x=0

<u>step2:-</u>

Again differentiating with respective to 'x', we get

f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}

on simplification , we get

f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}

put x= 0 we get f^{ll}(0) = \frac{2}{(1)^2}   > 0

f^{ll}(x) >0 then find the minimum value at x=0

<u>Final answer</u>:-

The minimum value of the given function is f(0) = 0

5 0
4 years ago
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