Answer:
After 48 hours amount left = 6.25 g
Explanation:
Given data:
Half life of potassium = 12 hours
Total mass = 100 g
Mass left after 48 hours = ?
Solution:
Number of half lives passed:
Number of half lives = Time elapsed / half life
Number of half lives = 48 hours/ 12 hours
Number of half lives = 4
At time zero = 100 g
At first half life = 100 g/ 2 = 50 g
At 2nd half life = 50 g/2 = 25 g
At 3rd half life = 25 g/2 = 12.5g
At 4th half life = 12.5 g/2 = 6.25 g
Available options are:
A. a scientific inquiry is used only by scientists.
B. scientific inquiry is a process of asking and answering questions.
C. scientific inquiry has only one correct pathway.
D. scientific inquiry often involves similar processes and practices.
E. scientific inquiry involves performing investigations and collecting data.
Answer:
B, D, E
Explanation:
Given that scientific inquiry is a term that described how people mostly scientists, observe the natural world and then come out with credible justification established on the findings that were derived.
Hence, the statements that describe scientific inquiry are:
1. B. scientific inquiry is a process of asking and answering questions. Through this, scientist want to understand the reason behind a certain phenomenon
2. D. scientific inquiry often involves similar processes and practices. To carry out scientific studies, certain steps and practices are required, regardless of the subject under study, which does not entirely change.
3. E. scientific inquiry involves performing investigations and collecting data. This is because to carry out a scientific inquiry, part of the steps and practice includes performing investigations and collecting data, regardless of the subject under study.
8. Glucose
9. NADH
10. 2 Pyruvic Acid
Answer:
25%
Explanation:
<em>The approximate proportion of G + C content in the genome of E. coli has been reported to be 50%. According to Chargaff's rule, the amount of guanine in any DNA must be approximately equal to the amount of cytosine. </em>Hence,
if G + C = 50 and G = C,
then
G = C = 25
Therefore, the approximate percentage of guanine in the genome of <em>E. coli </em>would be 25.
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