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yulyashka [42]
3 years ago
13

What is the circumference of the circle? (use 3.14 for pi) r = 50mm

Mathematics
1 answer:
Alexxandr [17]3 years ago
7 0

Answer:

Step-by-step explanation:

circumference = 2\pir

= 2 × 3.14 × 50

= 31.4 mm

hope this helps

plz mark it as brainliest !!!!!!!!!!!

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A plane is descending onto the runway with an angle of depression of 55°. If it has 2.8 miles to go before landing (hypotenuse),
nalin [4]

Answer:

Option C is correct

Step-by-step explanation:

Given: A plane is descending onto the runway with an angle of depression of 55°. Also, it has 2.8 miles to go before landing.

To find: current altitude of the plane

Solution:

Consider the attached image.

In ΔABC,

\angle ACB=55^{\circ} (Alternate interior angles)

For any angle \theta,

tan \theta = side opposite to angle/side adjacent to angle

\tan C=\frac{AB}{BC}

Put \angle C=55^{\circ}\,,\,BC=2.8\,\,miles

AB=2.8\,\tan 55^{\circ}=3.999\approx 4\,\,miles

So, the current altitude of the plane is 4 miles.

Download pptx
4 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
SIZIF [17.4K]
C = 4M + 5
4M = C - 5
  M = (C - 5)/4

answer is D. Last one.
6 0
4 years ago
If a+b+c =0 show that a³+b³+c³= 3abc
slega [8]

Answer:

Step-by-step explanation:

a+b+c=0, a+b=-c,a+c=-b, b+c=-a

(a+b+c)^3=(a+b+c)^2*(a+b+c)=(a^2+b^2+c^2+2ab+2ac+2bc)*(a+b+c)=

a^3+ab^2+ac^2+2a^2b+2a^2c+2abc+a^2b+b^3+bc^2+2ab^2+2abc+2b^2c+a^2c+b^2c+c^3+2abc+2ac^2+2bc^2=a^3+b^3+c^3+3a^2b+3a^2c+3ac^2+3ab^2+3bc^2+3b^2c+6abc=

a^3+b^3+c^3+3a^2*(b+c)+3c^2(a+b)+3b^2(a+c)+6abc=

a^3+b^3+c^3+3a^2*(-a)+3c^2*(-c)+3b^2*(-b)+6abc=

a^3+b^3+c^3-3a^3-3c^3-3b^3+6abc=

6abc-2a^3-2b^3-2c^3=2(3abc-a^3-b^3-c^3)=

2*[3abc-(a^3+b^3+c^3)]=0

so 3abc-(a^3+b^3+c^3)=0

so a^3+b^3+c^3=3abc

7 0
3 years ago
There are 2 Rectangles, a red one and a blue one.The Blue rectangle has the perimeter of 250 km. If the area of the red rectangl
kap26 [50]

Answer:a

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please help me ASAP. This is for Trigonometry, Math
Rufina [12.5K]

Answer:  C) exactly one triangle

<u>Step-by-step explanation:</u>

Given: ∠A = 45°, ∠B = 65°, side c = 4 cm

By the Triangle Sum Theorem, ∠C = 70°

Now you have a proportion so you can use the Law of Sines to find the exact length of side a and of side b.

\dfrac{\sin\angle A}{a}=\dfrac{\sin\angle B}{b}=\dfrac{\sin\angle C}{c}\\\\\\\dfrac{\sin 45^o}{a}=\dfrac{\sin65^o}{b}=\dfrac{\sin70^o}{4}

Thus, there is exactly one triangle.

5 0
4 years ago
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