Answer: yes, it is
Step-by-step explanation:
A number is divisible by 6 if it is divisible by 2 and 3 simultaniously.
n = k(k+1)(k-1)
If k-1 is a multiple of 3, n is divisible by 3, so one of the requirements is ok.
Now, if k-1 is a multiple of 3, it can be even or odd.
if k-1 is even, then it is divisible by 2 and as it is divisible by 3 as well, n is divisible by 6
if k-1 is odd, then k and k+1 is even, hence, divisible by 2.
As n = k(k+1)(k-1), n is also divisible by 6.
X varies directly as y would be
x vairies inversly as y would be
not sure if the y is on the bottom or on top from looking at the question
Let's convert the problem into Arithmetic progression:
It would be: 5, 9, 13, ....
Here, a = 5, d = 9 - 5 = 4
We know, S(n) = n/2 [ 2a + (n-1)d ]
Substitute the known values,
434 = n/2 [ 2(5) + (n - 1)4 ]
434 * 2 = n [ 10 + 4n - 4 ]
868 = 10n + 4n² - 4n
= 4n² + 6n - 868 = 0
d = b² - 4ac
d = 6² - 4(4)(-868)
d = 36+13888
d = 13924
Now, roots = -b +- √d / 2a
= (-6 + √13924) / 2(4) OR (-6 - √13924) / 2(4)
= (-6 + 118) / 8 OR (-6 - 118) / 8
= 112/8 OR -124/8
= 14 OR -15.5
As number of sticks can't be in negative/decimal or fraction form, -15.5 would be fully rejected.
In short, Your Answer would be 14 [ Remaining root ]
Hope this helps!
Answer:
495 min
Step-by-step explanation:
Answer:
5 word problems(4points each) & 10 open (3 points each)
Step-by-step explanation:
O= open response
W= word problems
W+O =15
4W + 3O = 50
multiply the first by -3 to eliminate O
-3W -3O = -45
4W + 3O = 50
AD BOTH
W = 5 ( 5 questions word problems)
O= 10 ( 10 questions open response)
5x4 = 20
10x3 = 30
20 + 30 = 50 points
