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N76 [4]
3 years ago
9

WHOEVER GETS THIS RIGHT IN 2MINS GET BRAINLIEST!1

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
7 0

Answer: The final is C.

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Given: ΔABC ≅ ΔEDF
V125BC [204]

we know that

the triangle ABC and triangle EDF are congruent triangles-----> given problem

therefore

AC=EF\\AB=ED\\BC=DF

we know that

the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Step 1

<u>Find the distance AB</u>

A(0,1)\\B(0,2)

substitute in the formula of the distance

d=\sqrt{(2-1)^{2}+(0-0)^{2}}

d=\sqrt{(1)^{2}+(0)^{2}}

dAB=1\ unit

Step 2

<u>Find the distance BC</u>

B(0,2)\\C(3,2)

substitute in the formula of the distance

d=\sqrt{(2-2)^{2}+(3-0)^{2}}

d=\sqrt{(0)^{2}+(3)^{2}}

dBC=3\ units

Step 3

<u>Find the distance AC</u>

we know that

the triangle ABC is a right triangle

so

Applying the Pythagorean Theorem

AC^{2}=AB^{2} +BC^{2}

substitute the values in the formula

AC^{2}=1^{2} +3^{2}

AC=\sqrt{10}\ units=3.16\ units

round to the nearest tenth

AC=3.2\ units

therefore

EF=3.2\ units

ED=1\ unit

DF=3\ units

<u>the answer is</u>

The length of the hypotenuse is equal to 3.2\ units

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Answer:

Using the slope-intercept form, the y-intercept is 7

Step-by-step explanation:

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