Answer:
The interval of increase of g(x) is 
.
Step-by-step explanation:
The interval of increase occurs when first derivative of given function brings positive values. Let be 
, the first derivative of the function is:
The following condition must be met to define the interval of increase:
The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:
The solution to this inequation is:
Now, the solution to this expression in interval notation is:
Answer:
3 (negative 64 divided by 8) + 25 = 1
Step-by-step explanation:
Negative 4 + (negative 5) (negative 6) divided by (negative 3) = -4 + (-5)(-6)/(-3) = -4 + 30/-3 = -4 - 10 = -14
8 Left-bracket 10 divided by (2) (negative 2) Right-bracket = 8(10/((2)(-2)) = -20
3 (negative 64 divided by 8) + 25 = 3(-64/8) + 25 = 3(-8) + 25 = -24 + 25 = 1
Negative 2 (negative 5) (negative 3) divided by 10 = (-2)(-5)(-3)/10 = -3
The only positive value here is 1, which is a result of 3 (negative 64 divided by 8) + 25
Answer:
29274
Step-by-step explanation:
Because 17*14=238 and 238*123=29274
Do you have an image that follows this question?
At the beining, he has 76
that is at x=0
y=mx+76
find m
given
when x=2, y=100
find m
100=2m+76
minus 76 both sides
24=2m
divide both sides by 2
12=m
the equatin is
y=12x+76
