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postnew [5]
3 years ago
12

Solve using the substitution method.

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
5 0

Answer:

x = 1, y = 4

Step-by-step explanation:

This is very simple

Since you have 2 equations with the same coefficient of x, just minus one equation from another:

          x + 3y = 13

       -      

          x + 2y = 9

                1y = 4

Sub y = 4 into any of the 2 equation,

x + 3(4) = 13

x + 12 = 13

x = 13 - 12

  = 1

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AP:3,15,27,39......

From the AP

a=3

a+d=15

a+2d=27

3+d=15 (1)

3+2d=27 (2)

Subtract (1) from (2)

We have,

2d-d=27-15

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=3+(54-1)12

=3+(53)12

=3+636

=639

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132+54th term

=132+639

=771

Find the term

771=a+(n-1)d

771=3+(n-1)12

771-3=12n-12

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n=780/12

=65

n=12

The term which is 132 more than the 54th term is the 65th term

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