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3 years ago

25/3 divided by 3/4 PLS HELP ITS FOR I READY

Mathematics

2 answers:

ch4aika [34]3 years ago

5 0

The answer is 11.1111111111

Vilka [71]3 years ago

4 0

Answer:

Step-by-step explanation:

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3 po

Stolb23 [73]

Answer: 360minutes

Step-by-step explanation:

Speed = space/time ; time = space/speed

space = 600km

speed: 100km/h

time = 600km/100km/h = 6hours

Since 1hour = 60minutes

6hours = 6x60minutes = 360 minutes

Answer: 360minutes

<h2><em>Spymore</em></h2>

3 0

4 years ago

The alphabet game costs $.25 to play. Before the game, 26 slips of paper with a different letter of the alphabet on it are put i

iragen [17]

Answer: 25/676

Step-by-step explanation:

Number of possible outcomes = 26

In other to win, one must draw must be either (A, E, I, O or U)

Therefore required drws to win = 5

First draw:

P(win) = Total required outcome / Total possible outcome

P(win) = 5/26

Second draw:

P(win) = Total required outcome / Total possible outcome

P(win) = 5/26

Therefore,

P(winning twice) = (5/26) × (5/26) = 25/676

3 0

4 years ago

Chang has 2 shirts: a white one and a black one. He also has 2 pairs of pants, one blue and one tan. What is the probability, if

Rom4ik [11]

Chang has a 50% probability of getting the white shirt and tan pants

8 0

3 years ago

Read 2 more answers

. In the design of an electromechanical product, 12 components are to be stacked into a cylindrical casing in a manner that mini

Harlamova29_29 [7]

Answer:

(a) 479,001,600 combinations (b) 95,040 combinations (c) 3,326,400 combinations

Step-by-step explanation:

(a) In the case we have 12 different elements to stack, the possible combinations can be calculated as a premutation of 12 elements:

P = 12! = 479,001,600 combinations

(b) If seven components are identical, we have a permutation with repetition.

We have 7!=5040 combinations that are the same, so there is only one unique out of 5040 combinations. We have to divide the total possible combinations by 5040.

P = 12! / 7! = 479,001,600 / 5,040 = 95,040 combinations

(c) In the same way, if we have 3 components of Type 1 and 4 components of Type 2 (and the others all different), we have 3!*4! = 144 combinations that are the same.

P = 12!/(3!*4!) = 479,001,600 / 144 = 3,326,400 combinations

3 0

4 years ago

115

alina1380 [7]

Answer:

70.5

Step-by-step explanation:

Firstly, we need to sort this list of numbers in order to perform calculations on it.

$31, 43, 47, 58, 63, 68, 69, 72, 77, 84, 84, 84, 94, 97$

To find the mean we must add up and divide by the amount of numbers there are.

$31 + 43 + 47 + 58 + 63 + 68 + 69 + 72 + 77 + 84 + 84 + 84 + 94 + 97 = 971\\\frac{971}{14}=69.3571429\approx 69$

To find the median we must find the number in the middle of the set.

As there are two numbers in the middle positions, 69 and 72.

We must take the average of these two numbers to determine the middle.

$\frac{69+72}{2}=70.5$

The most is the most common number, which is 84.

6 0

3 years ago