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Jet001 [13]
3 years ago
11

Evaluate 0.53n + 5 when n= 3 and when n= -3

Mathematics
1 answer:
vampirchik [111]3 years ago
4 0

Answer:

6.59 and 3.41

Step-by-step explanation:

To evaluate, substitute n for each of the given values.

So when n= 3:

0.53n + 5 = 1.59 + 5 = 6.59

And when n = -3

0.53 n + 5 = -1.59+5=3.41

Hope this helps

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24.3 miles to 1/2 hours
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3 years ago
Please anybody help me with this question
inn [45]

Answer:

y = 12

Step-by-step explanation:

Divide both by 1/4

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6 0
3 years ago
Suppose that the functions g and h are defined for all real numbers r as follows. gx) -4x +5 h (x) = 6x write the expressions fo
aleksandr82 [10.1K]

Answer: Our required values would be -10x+5, 2x+5 and -25.

Step-by-step explanation:

Since we have given that

g(x) = -4x+5

and

h(x) = 6x

We need to find  (g-h)(x) and (g+h)(x).

So, (g-h)(x) is given by

g(x)-h(x)\\\\=-4x+5-6x\\\\=-10x+5

and (g+h)(x) is given by

g(x)+h(x)\\\\=-4x+5+6x\\\\=2x+5

and (g-h)(3) is given by

-10(3)+5\\\\=-30+5\\\\=-25

Hence, our required values would be -10x+5, 2x+5 and -25.

5 0
3 years ago
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