Answer:
y = 2/7 or y = 14/25
Step by Step explanation:
sorry about the last answer
simplify both sides of the equation, then isolate the variable
We know that
∠ECD=∠ACB------> given in the problem
∠DEC=∠CAB------> 90°
so
∠EDC=∠ABC
therefore
triangles EDC and ABC are similar
<span>So
the ratio of the legs are equal</span>
![\frac{x}{9} = \frac{140-x}{81} \\ 81*x=9*(140-x) \\ 81x+9x=1260 \\ 90x=1260 \\ x=14](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B9%7D%20%3D%20%5Cfrac%7B140-x%7D%7B81%7D%20%20%5C%5C%2081%2Ax%3D9%2A%28140-x%29%20%5C%5C%2081x%2B9x%3D1260%20%5C%5C%2090x%3D1260%20%5C%5C%20x%3D14)
the answer isAC is equal to 126
Answer:
Step-by-step explanation:
xy = 300
x + y = 50 Solve for y
y = 50 - x substitute into xy = 300
x(50 - x) = 300 Remove the brackets.
50x - x^2 = 300 Bring the left to the right.
0 = x^2 - 50x + 300
This is a quadratic. It will have 2 solutions.
a=1
b = - 50
c = 300
Put these into the quadratic equation.
It turns out that x has two values -- both plus
x1 = 42.03
x2 = 6.97
x1 + y1 = 50
42.03 + y = 50
y = 50 - 42.03
y = 7,97
(42.03 , 7.97)
====================
x2 + y2 = 50
6.97 + y2 = 50
y2 = 50 - 6.97
y2 = 43.03
(6.97 , 43.03)
36 is the length of altitude of equilateral triangle below
Answer:
Step-by-step explanation:
-3y = -2x + 4
3y = 2x - 4
y = 2/3x - 4/3
perp; -3/2
y + 3 = -3/2(x - 4)
y + 3 = -3/2x + 6
y = -3/2x + 3