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alina1380 [7]
3 years ago
13

If x= (a^2)/b, which situation would always double the value of x? (1) Doubling the value of a (2) Halving the value of a (3) Do

ubling the value of b (4) Halving the value of b
Mathematics
1 answer:
MariettaO [177]3 years ago
5 0
(4) Halving the value of b

Example #1:
a = 4 , b = 2
x = (4^2) / 2
x = 16 / 2
x = 8
a = 4 , b = 1
x = (4^2) / 1
x = 16 / 1
x = 16

Example #2:
a = 8 , b = 4
x = (8^2) / 4
x = 64 / 4
x = 16
a = 8 , b = 2
x = (8^2) / 2
x = 64 / 2
x = 32
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ANEK [815]

Answer:

The matrix equation is \left[\begin{array}{ccc}1&1&1\\1&-1/2&0\\0&2&-1\end{array}\right]=\left[\begin{array}{c}120&35&20\end{array}\right]

Step-by-step explanation:

* Lets change the story problem to equations

- The distance between the starting point and checkpoint 1 is x

- The distance between checkpoint 1 to checkpoint 2 is y

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∴ x + y + z = 120 ⇒ (1)

-The distance from the starting point to checkpoint 1 is 35 miles

 more than half the distance from checkpoint 1 to checkpoint 2

∵ The distance from the starting point to checkpoint 1 is x

∵ The distance from checkpoint 1 to checkpoint 2 is y

- x is more than half y by 35

∴ x = 35 + (1/2) y ⇒ subtract (1/2) y from both sides

∴ x - (1/2) y = 35 ⇒ (2)

- The distance from checkpoint 2 to the finish line is 20 miles less

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∵ The distance from checkpoint 2 to the finish line is z

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- z is less than twice y by 20

∴ z = 2y - 20 ⇒ add 20 to both sides

∴ z + 20 = 2y ⇒ subtract z from both sides

∴ 2y - z = 20 ⇒ (3)

* Now lets write the three equations

# x + y + z = 120 ⇒ (1)

# x - (1/2) y = 35 ⇒ (2)

# 2y - z = 20 ⇒ (3)

- Now lets write the matrix equation that models this situation

∴ \left[\begin{array}{ccc}1&1&1\\1&-1/2&0\\0&2&-1\end{array}\right]=\left[\begin{array}{c}120&35&20\end{array}\right]

6 0
3 years ago
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Answer:
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6 0
3 years ago
Please help___________​
kramer

Answer:

Step-by-step explanation:

Let's do the obvious things first.

Right rectangle

w = 11

L = 17

Formula

Area = L * W

Area = 11 * 17

Area =                                                187

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W = 8

L = 11

Area = 8 * 11=                                      88

Middle Rectangle

W = 11

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Area = 11 * 15                                    165

Now we come to the triangles. It's not obvious what to do with them. You have to infer that one of the lets is 8 and the other is 15. You get the 8 from the width of the left rectangle (see above.)

There are 2 triangles

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Area = 2 * 1/2 (8 * 15)

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Total  = 120 + 165 + 88 + 187 =    560

Unless you have an  E answer that is 560, my answer does not agree with any of the given answers. I would suggest that you ask your teacher how it is done. My method is correct.

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Answer:

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