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alina1380 [7]
3 years ago
13

If x= (a^2)/b, which situation would always double the value of x? (1) Doubling the value of a (2) Halving the value of a (3) Do

ubling the value of b (4) Halving the value of b
Mathematics
1 answer:
MariettaO [177]3 years ago
5 0
(4) Halving the value of b

Example #1:
a = 4 , b = 2
x = (4^2) / 2
x = 16 / 2
x = 8
a = 4 , b = 1
x = (4^2) / 1
x = 16 / 1
x = 16

Example #2:
a = 8 , b = 4
x = (8^2) / 4
x = 64 / 4
x = 16
a = 8 , b = 2
x = (8^2) / 2
x = 64 / 2
x = 32
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Answer:

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5 0
2 years ago
Read 2 more answers
How to do the problem
marta [7]
There are 153 people who each ate 1/4 pounds. Therefore, the amount of watermelon eaten is 153/4 pounds.
The amount of watermelon served is
8 \frac{1}{4}  + 9 \frac{1}{4}  + 8 \frac{7}{8}  + 9 \frac{5}{8}  + 10 \frac{3}{4}
=  \frac{8 \times 4 + 1}{4}  +  \frac{9 \times 4 + 1}{4}  \\  +  \frac{8 \times 8 + 7}{8}  +  \frac{9 \times 8 + 5}{8} \\  +  \frac{10 \times 4 + 3}{4}
=  \frac{33}{4}  +  \frac{37}{4}  +  \frac{71}{8}  +  \frac{77}{8}  +  \frac{43}{4}  \\  =  \frac{33 \times 2}{4 \times 2}  +  \frac{37 \times 2}{4 \times 2}  +  \frac{71}{8}  \\  +  \frac{77}{8}  +  \frac{43 \times 2}{4 \times 2}
=  \frac{66 + 74 + 71 + 77 + 86}{8}
=  \frac{374}{8}  =  \frac{186}{4}
There is 186/4 total watermelon. Minus the 153/4 that was eaten,
\frac{186 - 153}{4}  =  \frac{33}{4}  = 8 \frac{1}{4}

The leftover watermelon is 8 & 1/4 pounds.
6 0
2 years ago
PLEASE HELP
alexgriva [62]

Answer:

Step-by-step explanation:

90.25$

5 0
1 year ago
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