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andre [41]
3 years ago
12

What's the percent of increase from 12 inches to 36 inches​

Mathematics
1 answer:
scoray [572]3 years ago
5 0
Answer: 200%


((36-12)/12)*100 = 200.00%
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Step-by-step explanation: 2000000 degrees celcius is

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A coordinate grid with 2 lines. The first line is labeled y equals 0. 5 x plus 3. 5 and passes through (negative 3, 1), (negativ
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Equation of the line is a way to represent the a line in a linear equation form with a set of point given in the graph.The approximate solution of the system given in the question is at point (-2.7,2.1). Thus the option A is correct.

<h3>Given-</h3>

The equation of the first lines which passes from the points (-3,1), (-2.7,2.1), and (0,3.5) is,

y=0.5x+3.5

The equation of the second line which passes from the points (-4,3),(-2.7,2.1), and ( 1/3,0) is,

y=-\dfrac{2}{3}x +\dfrac{1}{3}

<h3>Equation of the line</h3>

Equation of the line is a way to represent the a line in a linear equation form with a set of point given in the graph.

The two lines in the graph intersect each other at point (-2.7,2.1).

This intersection of two lines indicates that at the point of intersection the coordinates of that point are the solution for the two variables.

Hence, the approximate solution of the system given in the question is at point (-2.7,2.1). Thus the option A is correct.

For more about the coordinates, follow the link below-brainly.com/question/17514638

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2 years ago
A 2-column table with 4 rows. Column 1 is labeled Item Sold with entries Microwave Oven, Refrigerator, Dishwasher, Washing Machi
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- a - 5 + 12a - 9 + 7
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The answer is 11a -7 don’t go on brainly for math problems go on photo math. On photo math all you have to do is take a pic of the equation and it will answer it to you right away.
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3 years ago
A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
2 years ago
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