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Gre4nikov [31]
3 years ago
11

Juan went to the store to buy a plant for his mother, but forgot to ask which kind to get. Out of 30 plants, eighteen of them ar

e a kind that his mother would want. If Juan chooses one randomly, what is the probability that he will choose a kind that his mother would want?
Mathematics
1 answer:
Luba_88 [7]3 years ago
7 0

Answer:

Probability [Randomly choose plant Juan's mother want] = 3 / 5

Step-by-step explanation:

Given:

Total number of plant in store = 30 plants

Number of plant kind Juan's mother want = 18

Find:

Probability [Randomly choose plant Juan's mother want]

Computation:

Probability of an event = Number of favorable outcome / Total number of outcomes

Probability [Randomly choose plant Juan's mother want] = Number of plant kind Juan's mother want / Total number of plant in store

Probability [Randomly choose plant Juan's mother want] = 18 / 30

Probability [Randomly choose plant Juan's mother want] = 3 / 5

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Given that 1/(3^x) = 0.2<br> Find the value of (3^4)^x
bulgar [2K]
Hope this would help you

6 0
4 years ago
7.29 divided by 90 is ?
muminat

Answer:

<u>0.081</u>

Step-by-step explanation:

7.29 divided by 90 = <u>0.081</u>

6 0
3 years ago
In order to make green paint a 2:3 ratio of blue paint and yellow paint is used.If there are 30 ounces of green paint how many o
gladu [14]

Answer:

There are 30 ounce of green paint 18 ounces blue paint was needed.

Step-by-step explanation:

Given that,

In order to make green paint a 2:3 ratio of blue paint and yellow paint is used.

Assume 2x blue paint and 3x yellow paint required to make 30 ounce of green paint.

According to the problem,

2x+3x=30

⇒5x=30

\Rightarrow x=\frac {30}{5}

⇒ x=6

The amount of blue paint is = 2×6

                                              =12 ounces

The amount yellow paint is = (3×6)

                                            = 18 ounces

There are 30 ounce of green paint 18 ounces blue paint was needed.

6 0
3 years ago
A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the
creativ13 [48]

Answer:

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

2r+s=18

s=r \theta

2r+r \theta=18

solve for r

r=\frac{18}{2+\theta}

step 2

Find the value of s

s=r \theta

substitute the value of r

s=\frac{18}{2+\theta}\theta

step 3

we know that

The area of complete circle is equal to

A=\pi r^{2}

The complete circle subtends a central angle of 2π radians

so

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}

substitute the value of r

A=\frac{(\frac{18}{2+\theta})^2\theta}{2}

A=\frac{162 \theta}{(\theta+2)^2}

Convert to function notation

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

6 0
4 years ago
2 Name the diameter of the circle shown. <br>A co <br>B ec<br>C eo<br>D rc​
Orlov [11]

Answer: a

Step-by-step explanation:

6 0
3 years ago
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