Answer: (C) to reduce or eliminate future bank panics.
Explanation:
The Federal Reserve System being the central reserve system in the US was created with the primary objective of reducing and eliminating bank panics in periods of recessions and depressions and other bank related matters.
Answer:
The output is "A"
Explanation:
public class Solution {
public static void main(String args[]) {
mystery(7);
}
public static void mystery(int a) { System.out.println("A"); }
public static void mystery(double a) { System.out.println("B"); }
public static void mystery(int a, double b) { System.out.println("C"); }
public static void mystery(double a, int b) { System.out.println("D"); }
}
In the code above; mystery is defined in four different ways called method overloading. Method overloading is when same method is defined with different parameters.
In the first case; mystery will be called if the argument is int.
In the second case; mystery will be called if the argument is double.
In the third case; mystery will be called if the arguments are int and double.
In the fourth case; mystery will be called if the arguments are double and int.
When mystery(7) is called; the mystery method requiring only int will be called and the output is "A".
Answer:
def group_by_nondecreasing( *args ) :
num_list = [arg for arg in args]
sorted_numlist = sorted( num_list )
list_stream = [ sorted_numlist, sorted_numlist, sorted_numlist ]
return list_stream
Explanation:
This python function has the ability to accept multiple and varying amount of arguments. the list comprehension shorten the logical for statement to generate a list of numbers, sorts the list in ascending order by default and duplicates the list in another list.
In an if...else statement, if the code in the parenthesis of the if statement is true, the code inside its brackets is executed. But if the statement inside the parenthesis is false, all the code within the else statement's brackets is executed instead.
Of course, the example above isn't very useful in this case because true always evaluates to true. Here's another that's a bit more practical:
#include <stdio.h>
int main(void) {
int n = 2;
if(n == 3) { // comparing n with 3 printf("Statement is True!\n");
}
else { // if the first condition is not true, come to this block of code
printf("Statement is False!\n"); } return 0;
}
Output:
Statement is False!
Answer:
B. {1, 2, 2, 3, 3, 4, 5}
Explanation:
Given
The above code segment
Required
Determine which list does not work
The list that didn't work is 
Considering options (A) to (E), we notice that only list B has consecutive duplicate numbers i.e. 2,2 and 3,3
All other list do not have consecutive duplicate numbers
Option B can be represented as:
![nums[0] = 1](https://tex.z-dn.net/?f=nums%5B0%5D%20%3D%201)
![nums[1] = 2](https://tex.z-dn.net/?f=nums%5B1%5D%20%3D%202)
![nums[2] = 2](https://tex.z-dn.net/?f=nums%5B2%5D%20%3D%202)
![nums[3] = 3](https://tex.z-dn.net/?f=nums%5B3%5D%20%3D%203)
![nums[4] = 3](https://tex.z-dn.net/?f=nums%5B4%5D%20%3D%203)
![nums[5] = 4](https://tex.z-dn.net/?f=nums%5B5%5D%20%3D%204)
![nums[6] = 5](https://tex.z-dn.net/?f=nums%5B6%5D%20%3D%205)
if (nums.get(j).equals(nums.get(j + 1)))
The above if condition checks for duplicate numbers.
In (B), when the elements at index 1 and 2 (i.e. 2 and 2) are compared, one of the 2's is removed and the Arraylist becomes:
![nums[2] = 3](https://tex.z-dn.net/?f=nums%5B2%5D%20%3D%203)
![nums[4] = 4](https://tex.z-dn.net/?f=nums%5B4%5D%20%3D%204)
![nums[5] = 5](https://tex.z-dn.net/?f=nums%5B5%5D%20%3D%205)
The next comparison is: index 3 and 4. Meaning that comparison of index 2 and 3 has been skipped.
<em>This is so because of the way the if statement is constructed.</em>
