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Contact [7]
3 years ago
12

Create a method called letterGrade that will pass the student's average grade as a parameter and return a letter grade (char). O

nce passed, use an if..else if structure to determine whether the student has an A, B, C, D, or F. Return that letter grade. Use the standard grade scale: 90-100 (A), 80-89 (B), 70-79 (C), 60-69 (D), 0-59 (F).
Computers and Technology
1 answer:
Crank3 years ago
4 0

Answer:

The method in Java is as follows:

public static char letterGrade(int average){

    char grade =' ';

    if(average>= 90 && average <=100){ grade ='A'; }

    else if(average>= 80 && average <=89){ grade ='B'; }

    else if(average>= 70 && average <=79){ grade ='C'; }

    else if(average>= 60 && average <=69){ grade ='D'; }

    else if(average>= 0 && average <=59){ grade ='F'; }

    return grade;

}

Explanation:

This defines the method

public static char letterGrade(int average){

This initializes the grade to a blank

    char grade =' ';

If average is between 90 and 100 (inclusive), grade is A

<em>     if(average>= 90 && average <=100){ grade ='A'; }</em>

If average is between 80 and 89 (inclusive), grade is B

<em>     else if(average>= 80 && average <=89){ grade ='B'; }</em>

If average is between 70 and 79 (inclusive), grade is C

<em>     else if(average>= 70 && average <=79){ grade ='C'; }</em>

If average is between 60 and 69 (inclusive), grade is D

<em>     else if(average>= 60 && average <=69){ grade ='D'; }</em>

If average is between 0 and 59 (inclusive), grade is F

<em>     else if(average>= 0 && average <=59){ grade ='F'; }</em>

This returns the grade

    return grade;

}

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Explanation:

The following line declares the three variables

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If otherwise

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<em>  else { </em>

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