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zheka24 [161]
4 years ago
13

How do you find the GCF in a math problem?

Mathematics
1 answer:
anastassius [24]4 years ago
5 0

When we have two or more given numbers, we can find the largest factor that both numbers have in common. This is called the GCF or the Greatest Common Factor. ... Example: Find the GCF of 64 and 96. tep 1:

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What is the value of ?<br> HELP PLEASEEE !
Vikki [24]

Answer:

30

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST, 5/5 RATING, AND THANKS!!!!!!
aleksley [76]

Answer:

2 * 159 = 318

3 * 159 = 477

5 * 159 = 795

10 * 159 = 1590

3 0
3 years ago
Kamila has a rectangular lawn that measures 80 by 150 feet. She wants to lay gravel made from colored rock in a border, 6 feet w
alex41 [277]

Answer:

1)Diagram attached

2)8424

3)1404

4)1569

Step-by-step explanation:

1)

Diagram is attached

2)

How many square feet of the gravel will surround the lawn:

Converting yards into feet:

1 yard =3 feet

So 80 yard =80(3) feet

                   =240 feet

and 150 yard =150 (3) feet

                     =450 feet

Area of rectangle is given by :length X width

Area of the outer border = (6+ 240+ 6 ) (6+ 450+6)

                                         = 252 X 462

                                         = 116424

Area of the lawn = 240 X 450

                            = 108000

Area of gravel border = 116424 - 108000

                                    = 8424

Area of gravel border is 8424 ft^2

3)

Total volume when depth is 2 inches:

converting inches to feet:

1 inch=  0.083 feet

2 inches =0.1667 feet

volume = base area X depth

            =8424 X 0.1667

            = 1404

 total volume of gravel needed for the border is 1404 ft^3

4)

Given:

A large bag of colored rock contains 5/8 of a cubic yard and costs $30

total cost of the rocks needed for the border=?

1 cubic yard = $30

converting cubic yard to cubic feet

1 cubic yard=27 cubic feet

cost of 1 cubic yard= cost of 27 cubic feet = $ 30

cost of 1 cubic feet=30/27

cost of  1404 cubic feet= 1404 X 30 / 27

                                     = 1560

the total cost of the rocks needed for the border is $1560!

8 0
4 years ago
Use the intercepts of the following quadratic curve to find its graph.y = -1/2x^2 -3/2x+2
Solnce55 [7]

The correct graph is fourth option

Explanation:\begin{gathered} \text{The quadratic function:} \\ \text{y = }\frac{-1}{2}x^2\text{ - }\frac{3}{2}x\text{ + 2} \end{gathered}

Using the intercepts: we have x-intercept and y-intercept

To get x intercept, we will equate the function to zero. That is y = 0

\begin{gathered} 0\text{ = }\frac{-1}{2}x^2\text{ - }\frac{3}{2}x\text{ + 2} \\ mu\text{ltiply through by 2:} \\ 0=-x^2\text{ - 3x + 4} \\ x^2\text{ + 3x - 4 = 0} \\ x^2\text{ - x + 4x - 4 = 0} \\ x(x\text{- 1) +4(x - 1) = 0} \\ (x\text{ + 4)(x - 1) = 0} \\ x+4\text{ = 0 or x - 1 = 0} \\ x\text{ = -4 or x = 1} \end{gathered}

x intercepts are x = -4 and x = 1

This means the line will cross the x axis at two points: x = -4 and x = 1

To get y-intercept, we will equate x to zero:

\begin{gathered} \text{y = }\frac{-1}{2}(0)^2\text{ - }\frac{3}{2}(0)\text{ + 2} \\ y\text{ = 0 - 0 + 2} \\ y\text{ = 2} \end{gathered}

y-intercept = 2

This means the line will cross the y axis at y = 2

The correct graph is fourth option

8 0
1 year ago
The sample space of a random experiment is {a, b, c, d, e, f}, and each outcome is equally likely. A random variable is defined
Oksi-84 [34.3K]

Answer:

X ____ : 0 ______ 1.4 _____ 2 _____ 3

P(X) ___ 1/3 _____ 1/3 _____ 1/6 ____ 1/6 ;

0 ;

1/2 ;

0 ;

2/3 ;

1/2

Step-by-step explanation:

Each has the same probability ;

X ___ : 0 ___ 0 ___ 1.4 ____1.4 ___ 2 ___ 3

P(x) __ 1/6 __1/6 ___ 1/6 ___ 1/6 ___1/6 __ 1/6

Probability : required outcome / Total possible outcomes

X = 0

P(x = 0) = 1/6 + 1/6 = 2/6 = 1/3

X = 1.4

P(x = 1.4) = 1/6 + 1/6 = 2/6 = 1/3

X = 2

P(X) = 1/6

X = 3

P(x) = 1/6

Hence ;

X ____ : 0 ______ 1.4 _____ 2 _____ 3

P(X) ___ 1/3 _____ 1/3 _____ 1/6 ____ 1/6

A) P(X = 1.6).B) P(0.5 < X < 2.7).C) P(X > 3).D) P(0 ≤ X < 2).E) P(X = 0 or X = 2).

A.)

P(X = 1.6) = 0

B.)

P(0.5 < X < 2.7) = p(x = 1.4) + p(x = 2)

P(0.5 < X < 2.7) = 1/3 + 1/6 = (2 + 1) / 6 = 3/6 = 1/2

C.)

P(X > 3) = 0

D.)

P(0 ≤ X < 2) = P(0) + P(1.4)

P(0) + P(1.4) = 1/3 + 1/3 = 2/3

E.)

P(X = 0 or X = 2) = 1/3 + 1/6 = (2 + 1)/6 = 3/6 = 1/2

4 0
3 years ago
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