Question

In the equation (x+2)2+(y-3)2=4, the diameter of the circle is... 16 4 3 2

Answer 1

Answer:

4

Step-by-step explanation:

The given equation of circle is:

$(x+2)^2 +(y-3)^2 =4$

$(x+2)^2 +(y-3)^2 =2^2$

Equating it with:

$(x-h)^2 +(y-k)^2 =r^2$

We find:

$r^2=2^2$

$\therefore r=2$

Radius of the circle = 2 units

Therefore,

Diameter of the circle = 2*2= 4 units