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-BARSIC- [3]
3 years ago
14

3/4 divided by 1 1/2

Mathematics
2 answers:
Galina-37 [17]3 years ago
7 0
I got 0.5. You turn 1 1/2 into 3/2 and then find the reciprocal, which is 2/3. Then you multiply 3 and 2 which is 6.

4 and 3 is 12.

6/12 is 0.5 also known as 1/5
Ann [662]3 years ago
4 0

0.0340909091 is the answer

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Whats the value of 3x^2 + 5x when x=3 . show woro please if you can.
lubasha [3.4K]

Answer:

42

Step-by-step explanation:

3x^2 +5x

Let x=3

3(3)^2 +5(3)

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There are 6/8 of a cake leftover after a birthday party. How many 1/4 pieces can be made from the leftover cake?
marishachu [46]

Answer: 3

Step-by-step explanation:

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9th out of 10 questions
Mazyrski [523]

Hello! When dividing fractions, you multiply by the reciprocal of the second fraction. So 2/3 divided by 1/2 would be 2/3 times 2.

As you can see, the first fraction would be the same. Therefore, a will be 4. 5 and 6 will swap, so b will be 6 and c will be 5.

Therefore, our answer is D) a=4, b=6, c=5

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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
Viefleur [7K]

Answer:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

n = 1537, \pi = \frac{353}{1537} = 0.2297

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 - 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2087

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 + 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2507

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

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