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GenaCL600 [577]
3 years ago
8

A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other w

ords, the tank is not standing vertically on one of its flat ends.) If the radius of the cylinder is 0.5 meters, its length is 5 meters, and its top is 2 meters under the ground, find the total amount of work needed to pump the gasoline out of the tank. (The density of gasoline is 673 kilograms per cubic meter; use g=9.8 m/s2.)
Mathematics
1 answer:
hoa [83]3 years ago
6 0

Answer:

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

Step-by-step explanation:

Volume of cylinder = V

Radius of cylinder = r = 0.5 m

Height of the cylinder = 5 m

Volume of cylinder = \pi r^2h

V=3.14\times (0.5 m)^2\times 5 =3.925 m^3

Mass of gasoline = m

Density of gasoline = d = 673 kg/m^3

m=d\times V=673 kg/m^3\times 3.925 m^3=2,641.525 kg

Work done to pump the gasoline out of the tank W

Acceleration due to gravity = g .8 m/s^2

The center of gravity of fuel in fully filled tank will be centre so, the value of h = 2 m + 0.5 m = 2.5 m

W =m\times g\times h

W=2,641.525 kg\times 9.8 m/s^2\times 2.5 m=64,717.36 J

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

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