Question

A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other words, the tank is not standing vertically on one of its flat ends.) If the radius of the cylinder is 0.5 meters, its length is 5 meters, and its top is 2 meters under the ground, find the total amount of work needed to pump the gasoline out of the tank. (The density of gasoline is 673 kilograms per cubic meter; use g=9.8 m/s2.)

Answer 1

Answer:

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

Step-by-step explanation:

Volume of cylinder = V

Radius of cylinder = r = 0.5 m

Height of the cylinder = 5 m

Volume of cylinder = $\pi r^2h$

$V=3.14\times (0.5 m)^2\times 5 =3.925 m^3$

Mass of gasoline = m

Density of gasoline = d = $673 kg/m^3$

$m=d\times V=673 kg/m^3\times 3.925 m^3=2,641.525 kg$

Work done to pump the gasoline out of the tank W

Acceleration due to gravity = g $.8 m/s^2$

The center of gravity of fuel in fully filled tank will be centre so, the value of h = 2 m + 0.5 m = 2.5 m

$W =m\times g\times h$

$W=2,641.525 kg\times 9.8 m/s^2\times 2.5 m=64,717.36 J$

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.