Answer:
135.5ft
Step-by-step explanation:
THIS COMPLETE THE QUESTION
flagpole is supported by a wire fastened 60 feet from its base. The wire is 14 feet longer than the height it reaches on the flagpole. Find the length of the wire.
Let X be the length of the wire
Let y be the height of the pole
X= Y + 14
Y= X -14
We can form a right angle triangle form this, where X denote the Hypotenose, Y is the Opposite, and 60feet is the Adjacent.(CHECK THE ATTACHMENT FOR THE TRIANGLE)
Using Pythagoras theorem
X²= 60² + Y²
X² = 3600 + Y²
if we subsitute for Y we have
X² = 3600 + (X -14)²
X² = 3600 +X² -14X-14X+196
X²-X²+ 28X= 3600+196
28X= 3796
X= 3796/28
=135.5ft
hence length of the wire is 135.5ft
Answer:
m∠3 = 2x - 10° and m∠6 = 3x + 20
m∠3 = 58° ; m ∠6 = 122°
Step-by-step explanation:
a ║ b
m∠2 = m∠6 If ║ cut by a transversal, then corresponding angles
are ≅ and =
m∠7 = m∠3 If ║ cut by a transversal, then corresponding angles
are ≅ and =
m∠2 = 3x + 20 Given
m∠7 = 2x - 10 Given
m∠6 + m∠3 = 180° If ║ cut by a transversal, then each pair of same-side
interior angles (also called consecutive interior angles
are supplementary (sum = 180°) .
3x + 20 + 2x - 10 = 180°
5x + 10 = 180°
5x = 170°
x = 34°
Answer: m∠3 = 2x - 10° and m∠6 = 3x + 20
m∠3 = 2(34) - 10 ; m∠6 = 3(34) + 20
m∠3 = 58° ; m ∠6 = 122°
Answer:
I don't understand can you explain it differently?
Answer:
NO, It is<u> non terminating / recurring decimal</u>
Step-by-step explanation:
3/9= 0.33333333......
remainder= 3