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aivan3 [116]
3 years ago
7

A certain scale has an uncertainty of 4 g and a bias of 2 g. A single measurement is made on this scale. What are the bias and u

ncertainty in this measurement
Mathematics
1 answer:
Fed [463]3 years ago
6 0

Answer: 0.8

Step-by-step explanation:

given data:

uncertainity = 4g

bias = 2g

solution:

σX =0.2 and σY = 0.4

σcX

= 3σX

= 4(0.2)

= 0.8

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Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute
valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

       = 3 - 1 = 2

d.f.D = N - k

        = 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust                      Jet red                 Cloudtran

$\overline X_1 =50.5$           $\overline X_2 =50.07143$        $\overline X_3 =55.71429$

$s_1^2=19.96154$      $s_2^2=14.68681$         $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

         $=\frac{51+51+...+49+49}{35}$

        = 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

     $=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

   $=\frac{127.1143}{2}$

   = 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

    $=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

   $=\frac{669.8571}{32}$

  = 20.93304

The F-test  statistics value is :

$F=\frac{s_B^2}{s_W^2}$

  $=\frac{63.55714}{20.93304}$

  = 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source       Sum of squares    d.f    Mean square    F

Between    127.1143                 2      63.55714          3.036212

Within        669.8571             32      20.93304

Total           796.9714            34

3 0
2 years ago
What are all the common factors?
lord [1]

Answer:

2,3,6

Step-by-step explanation:

8 0
3 years ago
The ratio to hearts to moons is | The ratio of moons to all shapes is. I need help due in 10 minutes
Alinara [238K]

Hearts to moon= 6:4

                         = 3:2 (simplified)

Moon to all shapes= 4:10

                               = 2:5 (simplified)

4 0
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5 0
2 years ago
A car rental costs $50 for the first day. Additional days cost $35 per day, unless the car is rented for 7 days or more, in whic
son4ous [18]

Answer:

\$50+\$31.5x

Step-by-step explanation:

Let

x------> the number of days

y----> the cost of renting a car

we know that

For x

y=\$50+\$35x

For x\geq 7\ days

The rate is equal to

0.90*\$35=\$31.5

so

y=\$50+\$31.5x

In this problem. the car has been rented for more than a week

therefore

x> 7\ days

The cost of renting a car is equal to

y=\$50+\$31.5x

6 0
3 years ago
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