Considering that the data has no outliers, the mean of 3.2 inches should be used to describe the center of the data represented in this line plot.
<h3>What measure should be used to describe the center of a data-set?</h3>
It depends if the data-set has outliers or not.
- If it does not have outliers, the mean should be used.
- If it has, the median should be used.
The dot plot gives the number of times each measure appears. Since there is no outliers, that is, all values are close, the mean should be used. It is given by:
M = (2 x 1 + 3 x 2 + 2 x 3 + 1 x 5 + 1 x 6 + 1 x 7)/(2 + 3 + 2 + 1 + 1 + 1) = 3.2 inches.
The mean of 3.2 inches should be used to describe the center of the data represented in this line plot.
More can be learned about the mean of a data-set at brainly.com/question/24628525
Answer:
Therefore the required ways are =190
Step-by-step explanation:
Combination: Combination is the number of selection of items from a collection of items where the order of selection does not matter.
Total number of smartphones =22
Defective phone = 2
Non defective phone = (22-2) =20
The control inspector randomly test 4 smartphones of which 2 are defective.
Non defective phone = 2
The ways to select 2 non defective phone is
The ways to select 2 defective phone is= 
Therefore the required ways are = (190×1) =190
Answer:
C
Step-by-step explanation:
The graph can take any value of X
-3[ x^2 - 2x + 1] + 4
-3x^2 +6x -3 + 4
-3x^2 + 6x + 1
x can take any value of real numbers and there would be a solution
Hence all real numbers is the domain.
The variable in this algebraic expression is b
Solution: We are given:
μ=3.1,σ=0.5,n=50
We have to find P(Mean <2.9)
We need to first find the z score
z= (xbar-μ)/(σ/sqrt(n))
=(2.9-3.1)/(0.5/sqrt(50))
=(-0.2)/0.0707
=-2.83
Now we have to find P(z<-2.83)
Using the standard normal table, we have:
P(z<-2.83)=0.0023
Therefore the probability of the sample mean being less the 2.9 inches is 0.0023
