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Pavlova-9 [17]
3 years ago
8

Consider the equation y=2x+5 . Create a table of five ordered pairs that satify the equation. What is the y-intercept of the equ

ation? What is the x-intercept of the equation?
Mathematics
2 answers:
SOVA2 [1]3 years ago
6 0

Answer:

five ordered pairs are (-2,1) (-1,3) (0,5) (1, 7) (2, 9)

y intercept is (0,5)

x intercept is (-2.5, 0)

Step-by-step explanation:

y=2x+5

To get 5 ordered pairs , plug in some random number for x and find out y

x           y= 2x+5

-2            2(-2) + 5= 1

-1             2(-1) + 5= 3

0             2(0) + 5= 5

1             2(1) + 5= 7

2             2(2) + 5= 9

five ordered pairs are (-2,1) (-1,3) (0,5) (1, 7) (2, 9)

When x=0 , the value of y = 5

So y intercept is (0,5)

To find x intercept we plug in 0 for y

y=2x+5

0 = 2x +5

subtract 5 from both sides

-5 = 2x

divide by 2 on both sides

x= -5/2

so x intercept is (-2.5, 0)

kupik [55]3 years ago
5 0
Since y=mx+b is the slope-intercept form of a line, where m=slope and b=y-intercept, we can see that:

The y-intercept is 5 (technically the point (0,5))

The x-intercept occurs when y=0 so:

2x+5=0

2x=5

x=2.5

So the x-intercept is the point (2.5, 0)


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3 years ago
The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of
ser-zykov [4K]

Answer:

p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}, for r_{1} = 0

Step-by-step explanation:

The general form of quintic-order polynomial is:

p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f

According to the statement of the problem, the polynomial has the following roots:

p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)

Then, some algebraic handling is done to expand the polynomial:

p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)

p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x

If r_{1} = 0, then:

p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}

5 0
3 years ago
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