Solution :
Given initial velocity, v= 48 ft/s
Acceleration due to gravity, g = 
a). Therefore the maximum height he can jump on Mars is


= 96 ft
b). Time he can stay in the air before hitting the ground is


= 8 seconds
c). Considering upward motion as positive direction.
v = u + at
We find the time taken to reach the maximum height by taking v = 0.
v = u + at
0 = 16 + (12) t


We know that, 
Taking t =
, we get

feet
Thus he can't reach to 100 ft as it is shown in the movie.
d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.
Therefore final velocity is = -16 ft/s
Answer:
m<6 is 102°
Step-by-step explanation:
Angles that are supplementary are equal to a total of 180°.
Subtract the 78 from the 180 to find your answer.
180-78=102
Answer:
(0,0)
Step-by-step explanation:
The coordinates of C now are (-7,-5).
Moving C -3 on the x-axis will move -7 - 3 = -10. C is now located on (-10,-5).
Moving C +5 on the y-axis will move -5 + 5 = 0. C is now located on (-10,0).
Moving C on the y-axis +10 will move -10 + 10 = 0. C is now located on (0,0).
C is translated to (0,0).
Answer:
The percentage change is 140%
Step-by-step explanation:
Given
---- initial dimension
--- new width
--- new dimension
Required
The percentage increment
The length remains constant because only the width is extended.
The new area is:


Make L the subject

Substitute values for A and W


--- this is the length of the garden
Calculate the initial width:

Make W1 the subject



So, the initial area is:



The percentage change in area is:




Express as percentage


Answer:
Step-by-step explanation:
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