Sorry, I misinterpreted the question before.\\\\
4^20+4^20+4^20+4^20 \\\\
4(4^20)\\\\
4^21\\\\
Answer:
(3y - 2)(2y - 7)
Step-by-step explanation:
To factorise the quadratic
Consider the factors of the product of the coefficient of the y² term and the constant term which sum to give the coefficient of the y- term
Product = 6 × 14 = 84 and sum = - 25
The required factors are - 4 and - 21
Use these factors to split the y- term
6y² - 4y - 21y + 14 ( factor the first/second and third/fourth terms )
2y(3y - 2) - 7(3y - 2) ← factor out (3y - 2) from each term
= (3y - 2)(2y - 7) ← in factored form
C) 12V2
12^2 + 12^2 = c^2
144 + 144 = 288
V288 = 12V2
I just found 10% of it, which is 14, then found 5% of it through the previous work, which is 7
then i multiplied 7 by 11, because 55/5 is 11, so 55% of 140 is 77