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ozzi
3 years ago
13

What is -15x + 80 > 170

Mathematics
1 answer:
Korolek [52]3 years ago
3 0

Answer:

Step-by-step explanation:

Value of x should be  less than (-6).

x = { .......,-9,-8,-7}

For example:

-15*-7 +80 = 105+80 = 185 >170

You might be interested in
The value of a $3000 computer decreases about 30% each year. write a function for the computers value V(t)
den301095 [7]

Answer:

Function for given situation is : V(t)=3000(0.70)^t

Value of computer after 4 years = $720.3.

Step-by-step explanation:

Given that the value of a $3000 computer decreases about 30% each year. Now we need to write a function for the computers value V(t). then we need to find about how much will the computer be worth in 4 years.

It clearly says that value decreases so that means function represents decay.

For decay we use formula:

A=P(1-r)^t

where P=initial value = $3000,

r= rate of decrease =30% = 0.30

t= number of years

A=V(t) = future value

so the required function is V(t)=3000(1-0.30)^t

or V(t)=3000(0.70)^t

Now plug t=4 years to get the value of computer after 4 years.

V(4)=3000(0.70)^4

V(4)=720.3

Hence final answer is $720.3.

7 0
3 years ago
Read 2 more answers
What is 2/5 times 15/16
Flauer [41]
That is 30/80 that reduces down to 3/8
How u get it is 2 times 15 over 5 times 16 then divide 30 and 80 by 10 to get 3/8
6 0
3 years ago
Read 2 more answers
There are 10 girls and 8 boys in Mr Augellis class. If 5 more girls and 5 more boys join the class, will the ratio of girls to b
zimovet [89]
Yes they will stay the same
8 0
3 years ago
Solve 2x + 4 &gt; 16.<br> NEED ANSWER ASAP
antiseptic1488 [7]

Answer:

x>6

Step-by-step explanation:

2x > 16-4

x > 12/2

x > 6

7 0
3 years ago
Read 2 more answers
Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Alla [95]

Given:

The expression is:

2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

m+n=-6

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

P(x)=2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

P(2)=P(-1)              ...(i)

Substituting x=-1 in the given polynomial.

P(-1)=2(-1)^3+m(-1)^2+n(-1)+c

P(-1)=-2+m-n+c

Substituting x=2 in the given polynomial.

P(2)=2(2)^3+m(2)^2+n(2)+c

P(2)=2(8)+m(4)+2n+c

P(2)=16+4m+2n+c

Now, substitute the values of P(2) and P(-1) in (i), we get

16+4m+2n+c=-2+m-n+c

16+4m+2n+c+2-m+n-c=0

18+3m+3n=0

3m+3n=-18

Divide both sides by 3.

\dfrac{3m+3n}{3}=\dfrac{-18}{3}

m+n=-6

Hence proved.

7 0
3 years ago
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