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ozzi
2 years ago
13

What is -15x + 80 > 170

Mathematics
1 answer:
Korolek [52]2 years ago
3 0

Answer:

Step-by-step explanation:

Value of x should be  less than (-6).

x = { .......,-9,-8,-7}

For example:

-15*-7 +80 = 105+80 = 185 >170

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X-2y=0 ,x²-y²=3<br>by step​
masya89 [10]

Answer:

x=2, y=1

x=-2, y = -1

Step-by-step explanation:

x - 2y = 0

x = 2y

x² - y² = 3

(2y)² - y² = 3

3y² = 3

y² = 1

y = 1 or y = - 1

x = 2 or x = -2

5 0
3 years ago
How many solutions does the following equation have?<br> -5(2+1) = –22 + 10
Igoryamba

Answer:

0 real # solution

Step-by-step explanation:

b^2-4ac<1 is equal to 0 real number solution and

-5(2+1)=-22+10

-5(2+1)=-12

which is less than 1

7 0
2 years ago
How much cash do you need for a 5% down payment on a $500,000 house
LiRa [457]

Depends where. Normally it whould cost 17,500.

5 0
3 years ago
Read 2 more answers
FOR BRAINLIEST ASAP!!!
a_sh-v [17]

Answer:

Calculator cost = $34

Step-by-step explanation:

x + (x+140) = 208

2x + 140 = 208

x=34

7 0
2 years ago
A 40-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and the chain
daser333 [38]

Answer:

a) W₁ = 78400 [J]

b)Wt = 82320 [J]  

Step-by-step explanation:

a) W = ∫ f*dl      general expression for work

If we have a chain with density of 10 Kg/m, distributed weight would be

9.8 m/s² * 10 kg   = mg

Total length of th chain is 40 m, and the function of y at any time is

f(y) = (40 - y ) mg   where ( 40 - y ) is te length of chain to be winded

At the beggining we have to wind 40 meters   y = 0 at the end of the proccess  y = 40 and there is nothing to wind then:

f(y) = mg* (40 - y )

W₁ =  ∫f(y) * dy    ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy  ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy

W₁ = mg [ 40*y |₀⁴⁰   -  1/2 * y²  |₀⁴⁰    ⇒  W₁ = mg* [ 40*40 - 1/2 (40)² ]

W₁ = mg * [1/2]     W₁ = 10*9,8* ( 800 )

W₁ = 78400 [J]

b) Now we can calculate work to do if we have a 25 block and the chain is weightless

W₂ = ∫ mg* dy     ⇒    W₂  = ∫₀⁴⁰ mg*dy   ⇒    W₂  = mg y |₀⁴⁰

W₂ = mg* 40   = 10*9.8* 40  

W₂ = 3920 [J]

Total work

Wt = W₁  +  W₂        ⇒    Wt = 78400 + 3920

Wt = 82320 [J]

6 0
2 years ago
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