The first two is worth 2,000 and the second is worth 200.
The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
<h3>How to determine the number of real zeros?</h3>
The equation of the function is given as:

Expand the function

Reorder the terms

Factor the expression

Factor out x -1

Expand

Factorize
](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Bx%28x%20%2B%203%29%20%2B%202%28x%20%2B%203%29%5D%28x%20-%201%29)
Factor out x + 2

The function has been completely factored and it has 3 linear factors
Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
Read more about functions at:
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B 11.2 Have a good day :)
The correct answer is option 4! you have a good day as well
Parallel lines have same slope but different y-intercept. So they gave the equation y=4x-5 and the (0,3) where 3 is the y-intercept.
So the equation would be y=4x+3. HOPE THIS HELPS!!!!!!!!