Answer:
Mean: For this case would be not useful since in the stem leaf plot is difficult to find this measure with this chart
Step-by-step explanation:
We want construct a stem and leaf plot and we want to find the measure least useful.
And for this case if we analyze the option we have:
Range: That very useful and it can be extracted from the stem and leaf plot
Median: It could be easy to find it with the stem leaf plot
Mode: With a stem leaf plot we can find easily the most repeated value
Mean: For this case would be not useful since in the stem leaf plot is difficult to find this measure with this chart
Create a ratio and cross multiply
20x - 75 = 14x + 63
6x = 138
x=23
hope this helps :)
Answer:
A t-score of 2.0244 should be used to find the 99% confidence interval for the population mean
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 39 - 1 = 38
Now, we have to find a value of T, which is found looking at the t table, with 38 degrees of freedom(y-axis) and a confidence level of 0.99(
). So we have T = 2.0244.
A t-score of 2.0244 should be used to find the 99% confidence interval for the population mean
It's B.) The student’s answer is not reasonable. Estimation: 170 + 90 = 260
Answer:
The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.
Step-by-step explanation:
The mean sample of the sum of n random variables is

If
are indentically distributed and independent, like in the situation of the problem, then the variance of
will be the sum of the variances, in other words, it will be n times the variance of
.
However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus
and as a result, the standard deviation of
is the standard deviation of
divided by
.
Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:
- Restaurants: We have boxes with 9 salmon each, so it will be

- Grocery stores: Each carton has 49 salmon, thus the standard deviation is

- Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.