All categories

3 years ago

Sally has 35% off coupon. The total before tax came $23.95. how much did the item originally cost?

Mathematics

1 answer:

Alexxx [7]3 years ago

7 0

Answer:

$36.85

Step-by-step explanation:

23.95 and 35% discount

this means that $23.95 is 65% of the original value (100-35=65)

the highest common multiple of 35 and 65 is 5

so 65 divided by 5 is 13

23.95 divided by 13 is 1.8423...

then you take that number and times it by as many 5's are in 35 that would be 7

so the number times 7 is 12.89.....

now add this number to the original price and you have your answer $36.85

You might be interested in

What is the LCD of 10 and 15?

dem82 [27]

Answer:

The least common denominator, also called lowest common denominator (LCD), of 10 and 15 is 30.

Step-by-step explanation:

5 0

3 years ago

What is the value of x in the figure below?

Mrac [35]

Answer:

x = 125°

Step-by-step explanation:

180° - 55° = 125°

125°

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

4 0

2 years ago

Which could be the running speed of a human in meters per second?

kvv77 [185]

1 x 10. It is unlikely that someone will run 103 meters in a second, along with 1010.

5 0

3 years ago

What is the area of the shaded portion in the parallelogram below?<br>

tensa zangetsu [6.8K]

Answer:

Area of trapeze= (B+b):2×h

Therefore : (7+10):2×4=34

Good luck!

5 0

3 years ago

There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con

grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

$\square ABCD$

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$

$\angle BAC = \angle DCA$

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

$\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$

and

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$

So, the congruent sides and angles of △ABE and △CDE are:

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$ ---- S

$\angle BAC = \angle DCA$ ---- A

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$ or $\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$ --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0

2 years ago