Okay so, we switch out f(x) with y - I’m sure you know this and we get y=2+3x/x-2.
Now just interchange x and y -> x=2+3y/y-2, now multiply both sides with (y-2), we get (y-2)x=2+3y.
Multiply x with the brackets, getting xy-2x=2+3y. Move 3y to the left changing it’s sign, also for -2x to the right: xy-3y=2+2x.
Factor out y from (xy-3y) and get (3-x)y=2+2x - now divide both sides by (3-x) resulting in y=2+2x/3-x .
Answer:
y
=
2
x
−
1
Explanation:
First, we need to determine the slope of the line. The formula for determining the slope of a line is:
m
=
y
2
−
y
1
x
2
−
x
1
where
m
is the slope and the x and y terms are for the points:
(
x
1
,
y
1
)
and
(
x
2
,
y
2
)
For this problem the slope is:
m
=
3
−
−
1
2
−
0
m
=
3
+
1
2
m
=
4
2
m
=
2
Now, selecting one of the points we can use the point slope formula to find the equation.
The point slope formula is:
y
−
y
1
=
m
(
x
−
x
1
)
Substituting one of our points gives:
y
−
−
1
=
2
(
x
−
0
)
y
+
1
=
2
x
Solving for
y
to put this in standard form gives:
y
+
1
−
1
=
2
x
−
1
y
+
0
=
2
x
−
1
y
=
2
x
−
1
Answer linky
=
2
x
−
1
Explanation:
First, we need to determine the slope of the line. The formula for determining the slope of a line is:
m
=
y
2
−
y
1
x
2
−
x
1
where
m
is the slope and the x and y terms are for the points:
(
x
1
,
y
1
)
and
(
x
2
,
y
2
)
For this problem the slope is:
m
=
3
−
−
1
2
−
0
m
=
3
+
1
2
m
=
4
2
m
=
2
Now, selecting one of the points we can use the point slope formula to find the equation.
The point slope formula is:
y
−
y
1
=
m
(
x
−
x
1
)
Substituting one of our points gives:
y
−
−
1
=
2
(
x
−
0
)
y
+
1
=
2
x
Solving for
y
to put this in standard form gives:
y
+
1
−
1
=
2
x
−
1
y
+
0
=
2
x
−
1
y
=
2
x
−
1
Answer link
Answer:
x = 6
Step-by-step explanation:
All triangle angles add up to 180 so:
90 + 5x + 6 + 54 = 180
5x + 150 = 180
5x = 30
x = 6
Answer:
The answer to your question is 1,027
Answer:
A) See the picture
B) 14
C) 45%
Step-by-step explanation:
A) To create a histogram like the one on the picture you can use an online tool like socscistatistics where the number of classes is customizable
B) Because the question B and C have to be responded using a frequency table with 8 classes the answer is 14; the method of using cumulative frequency tables should only be considered as a way of estimation, that is because you obtain values that depend on your choice of class intervals. The way to get a better answer would be to use all the scores in the distribution
Pc1 = 100*(4/40) = 10
Pc2 = 100*(4/40) = 10
Pc3 = 100*(3/40) = 7.5
Pc4 = 100*(11/40) = 27.5
Pc5 = 100*(5/40) = 12.5
Pc6 = 100*(4/40) = 10
Pc7 = 100*(7/40) = 17.5
Pc8 = 100*(2/40) = 5
Pc8 + Pc7 + Pc6 + Pc5 + Pc4 + Pc3 + Pc2 = 90%
Therefore, From class 8 to class 2 is the top 90% of the applicants and the minimum score is 14.
C) Scores equal to or greater than 20 are from class 8 to class 5
Pc8 + Pc7 + Pc6 + Pc5 = 45%
