1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Olin [163]
4 years ago
9

Help ASAP!! Math problems

Mathematics
1 answer:
const2013 [10]4 years ago
5 0

Answer:

7. C

8. D

Step-by-step explanation:

7. The interest rate is 8% or .08. You find that by solving I=Prt (interest=original amount*rate*time in years)

8. The discounted price would be $48 (80*(1-.40)) Then you multiply that 48 by .08 and add that amount to the $48.

You might be interested in
Use the given information to determine which lines, if any , are parallel
Ksenya-84 [330]

Answer:

both are parrallel lines

5 0
4 years ago
How do you do inverse operation on a fraction ( y/3 ) = -6
NemiM [27]

\frac{-1}{18}

Solution:

Given expression is \frac{y}{3}=-6

To find the inverse of y.

⇒ \frac{y}{3}=-6

Do cross multiplication.

⇒ y = –6 × 3

⇒ y = –18

Inverse of y means reverse the function.

We know that inverse of y is \frac{1}{y}.

⇒ \frac{1}{y}= \frac{-1}{18}

Hence, inverse of y is \frac{-1}{18}.

4 0
3 years ago
When reading a book, Charlie made a list by writing down the page number of the last page he finished reading at the end of each
Assoli18 [71]

Answer:

No. of pages he read by the end of the 8th day = 425

Step-by-step explanation:

Charlie started from page 1 and read the same number of pages each day. Suppose x is the number of pages he read each day, the last page he read on the first day would be:

<u>Last page for day 1 = 1 + x</u>

This would be the first number he noted on the list.

The second page number can be determined by adding the number of pages he read to the last page for day 1.

Last page for day 2 = 1 + x + x

                                 = 1 + 2x

Similarly, the last page he read on the third day is:

Last page for day 3 = 1 + 3x. Similarly,

Last page for day 4 = 1 + 4x

Last page for day 5 = 1 + 5x

Last page for day 6 = 1 + 6x

Last page for day 7 = 1 + 7x

Last page for day 8 = 1 + 8x

His Mom added all of the page numbers and got a total of 432. So,

432 = 1+x + 1+2x + 1+3x + 1+4x + 1+5x + 1+6x + 1+7x + 1+8x

432 = 8 + 8x

8x = 432-8

8x = 424

x = 424/8

x = 53

By the end of the 8th day he actually read 1 + 8x pages. Substituting the value of x in this expression, we get:

No. of pages he read by the end of the 8th day = 1 + 8(53)

                                                                               = 1 + 424

No. of pages he read by the end of the 8th day = 425

4 0
4 years ago
9.2 HW Central Angles, Arc Measures, &amp; Arc Length
kap26 [50]

Answer:

I can help you with this, i just need the actual questions.

Step-by-step explanation:

5 0
3 years ago
Please show the answer with the work, GodBless.
Yanka [14]
Well, we know that y=1/2x+5 from the first equation. if we substitute that into the second equation, it becomes 2x + 1/2x +5 =1. solve for x. 2x+1/2x= -4, 2 1/2x=-4, x=-1.6. plug that in to one of the equations. 2(-1.6)+y=1, -3.2+y=1, y=-2.2. the solution is (-1.6, -2.2)
8 0
3 years ago
Other questions:
  • What is the simplified form of the equation (x-1/x-1) x+5/x+1 -x-2/x-1(x+1/x+1)
    13·1 answer
  • How would you write 0.7 in a fraction
    13·1 answer
  • ................. math help plssss ❤️❤️❤️
    9·2 answers
  • A square banner has an area of 289 square inches.
    10·1 answer
  • is the product if 19 negative numbers and 22 positive numbers a postive number or a negative number?​
    6·1 answer
  • How many solutions does 4(x-1)-x = 3(x+5)-11 have
    7·1 answer
  • 2/9 + 4/9 .........​
    12·2 answers
  • Sketch a graph to show your heart rate over the course of a work out. Explain<br> your graph.
    5·1 answer
  • Need help with it I don’t know how to do it
    9·1 answer
  • What is pollution ????,​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!