n, n + 2, n + 4 - three consecutive odd integers
The equation:
2n = 3(n + 4) + 15 |use distributive property
2n = (3)(n) + (3)(4) + 15
2n = 3n + 12 + 15
2n = 3n + 27 |subtract 3n from both sides
-n = 27 |change the signs
n = -27
n + 2 = -27 + 2 = -25
n + 4 = -27 + 4 = -23
Answer: -27, -25, -23.
<h3>
Answer: 41</h3>
Work Shown:
f(x) = 6x^2 - 13
f(x) = 6(x)^2 - 13
f(-3) = 6(-3)^2 - 13 ... replace every x with -3; use PEMDAS to simplify
f(-3) = 6(9) - 13
f(-3) = 54 - 13
f(-3) = 41
The value of the 8 is 800000
(I think you need a-e, if not let me know and I will edit accordingly)
a: Divide both sides by 4
cm -> 12:8
3:2
b: Convert and divide both sides by 3
cm -> 150:9
50:3
c: Convert and divide both sides by 20
cm -> 100:80
5:4
d: Convert and divide both sides by 4
months -> 4:12
1:3
e: Convert and divide both sides by 250
g -> 2000:250
8:1
Hope this helps, have a nice day :)
Answer: 41/10 or 4.1 or 4 1/10
explanation: multiple each fraction by the number on the bottom and simplify.
