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3 years ago

Can someone please help me on this math problem?

Mathematics

1 answer:

xz_007 [3.2K]3 years ago

5 0

Answer:

1. OG (with line on top)

2. MA (with line on top)

3. <O

4. <D

5. triangle ODG

6. triangle ADM

Step-by-step explanation:

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The sum of two numbers is 55. The larger number is 17 more than the other number. What is the value of the larger number? (Let t

Elis [28]

X+y=55
Y= X+17

X+ X+17=55
2x+17=55
Subtract 17
2x= 38
Divide by 2
X=19
Larger number 19+17=36
36

6 0

3 years ago

I need help with this

goblinko [34]

Yes because their both 90° angle triangles

3 0

4 years ago

Read 2 more answers

Solve the equation. 31-12n=211

Mashutka [201]

Answer:

Step-by-step explanation:

31 - 12n = 21l Subtract 31 from both sides.

31-31-12n =211-31 Do the subtraction

-12n = 190 Divide by -12

-12n/-12 = 190/-12

n = -15.333333

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4 years ago

What happens when y = -f(-x)?

IgorLugansk [536]

Answer:

It's a reflection over the x axis.

Step-by-step explanation:

Idk I googled it.

3 0

3 years ago

Simplify ^3 sq try (-0.05)^24

Bogdan [553]

Answer:

$\sqrt[3]{\left(-0.05\right)^{24}}=0.05^8$

so option D is correct.

Step-by-step explanation:

Given the expression

$\sqrt[3]{\left(-0.05\right)^{24}}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\sqrt[3]{\left(-0.05\right)^{24}}=\left(\left(-0.05\right)^{24}\right)^{\frac{1}{3}}$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}$

$=\left(-0.05\right)^{24\cdot \frac{1}{3}}$

$=\left(-0.05\right)^8$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}$

$=0.05^8$

Hence, the simplification will be:

$\sqrt[3]{\left(-0.05\right)^{24}}=0.05^8$

Therefore, option D is correct.

7 0

3 years ago