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ohaa [14]
3 years ago
13

Simplify ^3 sq try (-0.05)^24

Mathematics
1 answer:
Bogdan [553]3 years ago
7 0

Answer:

As

  • \sqrt[3]{\left(-0.05\right)^{24}}=0.05^8

so option D is correct.                    

Step-by-step explanation:

Given the expression

\sqrt[3]{\left(-0.05\right)^{24}}

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}

\sqrt[3]{\left(-0.05\right)^{24}}=\left(\left(-0.05\right)^{24}\right)^{\frac{1}{3}}

\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}

                  =\left(-0.05\right)^{24\cdot \frac{1}{3}}

                  =\left(-0.05\right)^8  

\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}

                  =0.05^8

Hence, the simplification will be:

\sqrt[3]{\left(-0.05\right)^{24}}=0.05^8

Therefore, option D is correct.                                            

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