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3 years ago

In the diagram which two angles must be supplementary with angle 6? A.5 and 7 B. 1 and 10 C.14 and 16 D.7 and 11

Mathematics

2 answers:

gregori [183]3 years ago

8 0

Answer:

Option A. 5 and 7

Step-by-step explanation:

we know that

If two angles are supplementary, then their sum is equal to 180 degrees

In this problem

m∠5+m∠6=180° -----> by supplementary angles (form a linear pair)

m∠6+m∠7=180° -----> by supplementary angles (form a linear pair)

therefore

Angle 5 and angle 7 are supplementary with angle 6

anastassius [24]3 years ago

4 0

Answer:

Option A, angle 5 and angle 7

Explanation:

I just took that test on E d g e n u i t y and it was right

Have a greatastic day!! $^u^$

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pogonyaev

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So then we need to find BC.

We know:
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3 years ago

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Mice21 [21]

Answer:

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3 years ago

Find the value of k so that the graph of 13y + kx = 4 and the line containing the points (5, -8) and (2, 4) are parallel.

guajiro [1.7K]

the graph of 13y + kx = 4 and the line containing the points (5, -8) and (2, 4) are parallel.

We find the slope of parallel line using two given points

(5, -8) and (2, 4)

Slope formula is

$slope = \frac{y_2-y_1}{x_2-x_1}$

$slope = \frac{4-(-8)}{2-5}$

$slope = \frac{12)}{-3}=-4$

so slope = -4

Slope of any two parallel lines are always equal

Lets find the slope of the equation 13y + kx = 4

Subtract kx on both sides

13 y = -kx + 4

Divide both sides by 13

$y= \frac{-kx}{13} + \frac{4}{13}$

Now slope = -k/13

We know slope of parallel lines are same

So the slope of 13y + kx = 4 is also -4

Hence we equation the slope and find out k

$\frac{-k}{13}=-4$

Multiply by 13 on both sides and divide by -1

k = 52

the value of k = 52

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3 years ago

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