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galben [10]
3 years ago
9

In the diagram which two angles must be supplementary with angle 6? A.5 and 7 B. 1 and 10 C.14 and 16 D.7 and 11

Mathematics
2 answers:
gregori [183]3 years ago
8 0

Answer:

Option A. 5 and 7

Step-by-step explanation:

we know that

If two angles are supplementary, then their sum is equal to 180 degrees

In this problem

m∠5+m∠6=180°  -----> by supplementary angles (form a linear pair)

m∠6+m∠7=180°  -----> by supplementary angles (form a linear pair)

therefore

Angle 5 and angle 7 are supplementary with angle 6

anastassius [24]3 years ago
4 0

Answer:

Option A, angle 5 and angle 7

Explanation:

I just took that test on E d g e n u i t y and it was right

Have a greatastic day!! \(^u^\)

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For the years between 1980 and 2012, the function c(x)=0.006x^3−0.48x^2+12.8x+85 approximates the number of countries that atten
Evgesh-ka [11]

Answer:

  199

Step-by-step explanation:

2004 is 24 years after 1980. The polynomial remainder theorem tells you the remainder from division by x-24 will be the function value c(24). We can find the remainder/function value by evaluating the function rewritten to Horner form:

  c(x) = ((0.006x -0.48)x +12.8)x +85

  c(24) = ((0.006(24) -0.48)(24) +12.8)(24) +85 = (-.336(24) +12.8)(24) +85

  = 4.736(24) +85 = 198.664

  c(24) ≈ 199

The approximate number of countries attending the 2004 Olympics was 199.

5 0
3 years ago
Two angle measures in a scalene triangle are 38° and 25°. What is the measure of the third angle?
NISA [10]
117, just add the two and subtract from 180
5 0
3 years ago
Read 2 more answers
Solve 2x+y=3 x+y=5 in substitution method
Nastasia [14]
2x+y=3
- x+y=5
---------------
x=-2

2(-2)+y=3
y=7

-2+y=5
y=7

(-2,7)
4 0
3 years ago
Please help me!
Tomtit [17]
One question, are they congruent figures?
7 0
3 years ago
Can anybody help me?
Sloan [31]

Answer:

7⅓

Step-by-step explanation:

2 ÷ 3⁄11 → 2 × 3⅔ >> 7⅓

Dividing by a fraction is the exact same as multiplying by its multiplicative inverse.

* 3⅔ = 11⁄3

* 7⅓ = 22⁄3

I am joyous to assist you anytime.

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3 years ago
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