Select the correct equation that describes the table below

Use the graph that shows the solution to

Luda [366]

Answer:

The solution for f(x) = g(x) are;

x = 1 and x = -1

Step-by-step explanation:

The given equations for the functions, g(x) are;

$f(x) = \dfrac{1 + 2\cdot x}{x}$

g(x) = 2 + x

The solution for f(x) = g(x), is given by equating the equations of the two functions as follows;

When f(x) = g(x), we have;

$\dfrac{1 + 2\cdot x}{x} = 2 + x$

By cross multiplication, we have;

1 + 2·x = x × (2 + x) = 2·x + x²

∴ x² + 2·x - 2·x - 1 = 0

x² - 1 = 0

(x - 1)·(x + 1) = 0

x = 1, or x = -1

f(x) = g(x) = 2 + 1 = 3, or 2 - 1 = 1

Therefore, the solution for f(x) = g(x) are;

f(x) = g(x) = 3 or 1 where x = 1 and x = -1.

6 0

2 years ago

Nina owns a vacation home valued at $75,500. She owes $32,126 on her mortgage. How much are the asset and liability values for N

alexandr402 [8]

The value of Nina's house is $75,500. However, she owes $32,126 on her mortgage.
The asset on her house is $75,500
The liability on her house is $32,156
The net worth of the house is $43,344 (difference between assets and liabilities)

5 0

3 years ago

If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?

enyata [817]

Step-by-step explanation:

$\bf➤ \underline{Given-} \\$

$\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\$

$\bf➤ \underline{To\: find-} \\$

$\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\$

$\bf ➤\underline{Solution-} \\$

Let us assume that:

$\rm: \longmapsto u = {x}^{2013}$

Therefore, the equation becomes:

$\rm: \longmapsto u + \dfrac{1}{u} = 2$

$\rm: \longmapsto \dfrac{ {u}^{2} + 1}{u} = 2$

$\rm: \longmapsto{u}^{2} + 1 = 2u$

$\rm: \longmapsto{u}^{2} - 2u + 1 =0$

$\rm: \longmapsto {(u - 1)}^{2} =0$

$\rm: \longmapsto u = 1$

Now substitute the value of u. We get:

$\rm: \longmapsto {x}^{2013} = 1$

$\rm: \longmapsto x = 1$

Therefore:

$\rm: \longmapsto {x}^{2022} + \dfrac{1}{ {x}^{2022} } = 1 + 1$

$\rm: \longmapsto {x}^{2022} + \dfrac{1}{ {x}^{2022} } = 2$

★ Which is our required answer.

$\textsf{\large{\underline{More To Know}:}}$

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0

3 years ago

4x-5=7+4y How do you solve?

solong [7]

solve for x.

4x−5=7+4y

Add 5 to both sides.

4x−5+5=4y+7+5

4x=4y+12

Divide both sides by 4.

4x/4=4y+12/4

x=y+3

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Have a nice day! :)

5 0

3 years ago

The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed, with mean o

prohojiy [21]

Answer:

The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%

Step-by-step explanation:

For a normal random variable with mean Mu = 3.2 and standard deviation sd = 0.8 there is a distribution of the sample mean (MX) for samples of size 4, given by:

Z = (MX - Mu) / sqrt (sd ^ 2 / n) = (MX - 3.2) / sqrt (0.64 / 4) = (MX - 3.2) / 0.4

For a sample mean of 3.0, Z = (3 - 3.2) / 0.4 = -0.5

For a sample mean of 3.0, Z = (4 - 3.2) / 0.4 = 2.0

P (3.2 <MX <4) = P (-0.5 < Z <2.0) = 0.6687.

The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%

6 0

3 years ago