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skelet666 [1.2K]
3 years ago
6

What is 3/5 * 1/3= 1/3 *

Mathematics
1 answer:
Elena-2011 [213]3 years ago
4 0

Answer:

3/5 * 1/3= 1/3, That is false but 3/5 * 1/3 = 1/5

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If the diameter of a circle with a circumference of 12.6 mm is divided by 2, what is the circumference of the new circle?
Archy [21]
12.6/2=6.3 is the answer hope it is helpful
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3 years ago
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Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
vichka [17]

Answer:

A(-1,0) is a local maximum point.

B(-1,0)  is a saddle point

C(3,0)  is a saddle point

D(3,2) is a local minimum point.

Step-by-step explanation:

The given function is  

f(x,y)=x^3+y^3-3x^2-3y^2-9x

The first partial derivative with respect to x is  

f_x=3x^2-6x-9

The first partial derivative with respect to y is  

f_y=3y^2-6y

We now set each equation to zero to obtain the system of equations;

3x^2-6x-9=0

3y^2-6y=0

Solving the two equations simultaneously, gives;

x=-1,x=3  and y=0,y=2

The critical points are

A(-1,0), B(-1,2),C(3,0),and D(3,2).

Now, we need to calculate the discriminant,

D=f_{xx}(x,y)f_{yy}(x,y)-(f_{xy}(x,y))^2

But, we would have to calculate the second partial derivatives first.

f_{xx}=6x-6

f_{yy}=6y-6

f_{xy}=0

\Rightarrow D=(6x-6)(6y-6)-0^2

\Rightarrow D=(6x-6)(6y-6)

At A(-1,0),

D=(6(-1)-6)(6(0)-6)=72\:>\:0 and f_{xx}=6(-1)-6=-18\:

Hence A(-1,0) is a local maximum point.

See graph

At B(-1,2);

D=(6(-1)-6)(6(2)-6)=-72\:

Hence, B(-1,0) is neither a local maximum or a local minimum point.

This is a saddle point.

At C(3,0)

D=(6(3)-6)(6(0)-6)=-72\:

Hence, C(3,0) is neither a local minimum or maximum point. It is a saddle point.

At D(3,2),

D=(6(3)-6)(6(2)-6)=72\:>\:0 and f_{xx}=6(3)-6=12\:>\:0

Hence D(3,2) is a local minimum point.

See graph in attachment.

3 0
3 years ago
The growth rate of the sunflower from day 14 to day
nata0808 [166]

Option B) h = 4.5t – 27 is the equation of the straight line that best models the height h, in centimeters, of the sunflower t days after it begins to grow.

                     

From the above graph we can see that from day 14 to day 35 , it is a straight line.

And equation of a straight line is   y = mx + c  or   y – y1 = m(x – x1)

                               Where, m =slope of the line

                                             c = intercept

the equation can be rewritten as  h – h1  = m(t – t1)                    (1)

So, to find the equation of line , first we will calculate the slope of the line.

To find the slope : m = (h2 – h1 ) / (t2 – t1)                     (2)

From the graph and the table given, the coordinates (t1 , h1 ) and ( t2 , h2 ) are (14 , 36.6) and (35, 131) respectively.

Putting these values in equation (2), we get

                 m = (131 – 36.6)/(35 – 14)

                 m =  94.4/21

                 m  = 4.5

now to find the equation of line we put the values in equation (1), we get

h – 36.6 = 4.5(t – 14)

h – 36.6 = 4.5t – 63

h = 4.5t -63 + 36.6

h = 4.5t -27

Hence the equation of the line is ,   option B) h = 4.5t -27

Learn more about the straight line here : brainly.com/question/6977417

#SPJ4

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904.32

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