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denis-greek [22]
3 years ago
14

13. Which equation has no solution? (1 point)A. 5v + 3 = 5v – 5 B. 2x – 4 = 2x + 7 – x C. 2y + 5 – y = 2y – 3(y – 6) D. 7z + 9 =

–7z – 6
Mathematics
1 answer:
sergeinik [125]3 years ago
8 0
D is the answer because you cancel out the 7z's and you are left with 9=-6
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77 prime or composite
Ludmilka [50]

<u><em>Seventy-seven is a composite number. </em></u>

Because you had to divide by eleven or seven. Then you can multiply by seven or eleven its equal to seventy-seven.

77/11=7

11*7=77

77/7=11

7*11=77

Final answer: \boxed{=77}

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

7 0
3 years ago
A group of 40 children attend a baseball game. Each child received either a hotdog or a bag of popcorn. Hotdogs were $2.25 and p
lions [1.4K]

Answer:

  • 27 hot dogs
  • 13 bags of popcorn

Step-by-step explanation:

Had all received popcorn, the bill would have been 40×$1.75 = $70. The bill was $13.50 more than that. Each hot dog purchased in place of popcorn adds $0.50 to the bill, so the number of hot dogs must be ...

  $13.50/$0.50 = 27

Of course, the remainder of the 40 items were popcorn, so 13 bags of popcorn.

27 hot dogs and 13 bags of popcorn were purchased.

8 0
3 years ago
A museum sold 95 tickets for $1,025. Each adult ticket was $15, and each child ticket was $7. Let a represent the number of adul
Genrish500 [490]

Answer:

a + c = 95........eq1

15a + 7c = 1,025....eq2

Step-by-step explanation:

Given:

Total number of ticket sold = 95

Total amount collected = $1,025

Price of each adult ticket = $15

Price of each child ticket = $7

Computation:

Number of adult tickets sold = a

Number of child tickets sold = c

So,

Number of adult tickets sold + Number of child tickets sold = Total number of ticket sold

a + c = 95........eq1

and

15a + 7c = 1,025....eq2

4 0
2 years ago
What is the solution to the inequality 2n+5| &gt; 1?
hodyreva [135]

Answer:

n < - 3 or n > - 2

Step-by-step explanation:

Inequalities of the type | x | > a , have solutions of the form

x < - a or x > a

Then

2n + 5 < - 1 or 2n + 5 > 1

Solve both inequalities

2n + 5 < - 1 ( subtract 5 from both sides )

2n < - 6 ( divide both sides by 2 )

n < - 3

OR

2n + 5 > 1 ( subtract 5 from both sides )

2n > - 4 ( divide both sides by 2 )

n > - 2

Solution is n < - 3 or n > - 2

3 0
3 years ago
Evaluate the following expressions if ×=2,y=3 and Z=4. a.4×+×-3over ×+10 b.2y-5yover y+5. c.yz-×. d.9+y+zover y+2​
sammy [17]

Answer:

A= 7 11/12 or 7.916 or  95.12

B= 4 1/8 or 4.125 or 33/8

C=  12 4/5 or 12.8 or 64/5

6 0
3 years ago
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