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vredina [299]
3 years ago
6

What is the Range of 100, 75, 40, 90, 80, 100, 92, 88, 80, 84, 81?

Mathematics
2 answers:
ale4655 [162]3 years ago
7 0

Answer:

60

Step-by-step explanation:

100 is the greatest value, 40 is the lowest 100-40=60

nasty-shy [4]3 years ago
7 0

Answer:

60

Step-by-step explanation:

I was born with glass bones and paper skin. Every morning I break my legs, and every afternoon I break my arms. At night, I lie awake in agony until my heart attacks put me to sleep.

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I NEED HELP AS SOON AS POSSIBLE
Xelga [282]
The answer is D. 200m = 2cm. That's because to get from meters to centimeters, you need to multiply by 100. 200 * 100 is not 2, therefore D is the answer. 
8 0
3 years ago
Read 2 more answers
Find an equation of the sphere containing all surface points P = (x, y, z) such that the distance from P to A(−3, 6, 3) is "twic
Marina86 [1]

Answer:

Equation of Sphere =  x^{2} + y^{2} + z^{2} - 18x - 4/3y +10z + 142/3 = 0

Step-by-step explanation:

Data Given:

P = (x,y,z)

Distance from P to A (-3,6,3) = Twice the distance from P to B(6,2,-3)

Solution:

Find the equation of the sphere:

It is given that:

PA = 2PB

Squaring both sides:

(PA)^{2} = (2PB)^{2}

(PA)^{2} = 4 (PB)^{2}

(x - (-3))^{2} + (y - 6)^{2} + (z-3)^{2} = 4 x (x-6)^{2} + (y-2)^{2} + (z-(-3))^{2}

Solving the above equation:

(x + 3))^{2} + (y - 6)^{2} + (z-3)^{2} = 4 x {(x-6)^{2} + (y-2)^{2} + (z + 3))^{2}}

x^{2} + 9 + 6x + y^{2} + 36 - 12y + z^{2} + 9 - 6z = 4 { x^{2} + 36 - 12x + y^{2} + 4 - 4y + z^{2} + 9 + 6z}

x^{2} + 9 + 6x + y^{2} + 36 - 12y + z^{2} + 9 - 6z = 4x^{2} + 144 - 48x +4y^{2} + 16 - 16y + 4z^{2} + 36 + 24z

Putting the right hand side = 0 and solving the equation:

x^{2} - 4x^{2} + y^{2} - 4y^{2} + z^{2} - 4z^{2} + 6x + 48x - 12y +16y -6z - 24z + 9 + 36 + 9 -144 - 16 - 36 = 0

-3x^{2} - 3y^{2}  -3z^{2}  + 54x + 4y -30z -142  = 0

Taking (-) common

- ( 3x^{2} + 3y^{2} + 3z^{2}  - 54x - 4y +30z + 142) = 0

3x^{2} + 3y^{2} + 3z^{2}  - 54x - 4y +30z + 142 = 0

dividing the whole equation by 3

x^{2} + y^{2} + z^{2} - 54/3x - 4/3y +30/3z + 142/3 = 0

x^{2} + y^{2} + z^{2} - 54/3x - 4/3y +30/3z + 142/3 = 0

x^{2} + y^{2} + z^{2} - 18x - 4/3y +10z + 142/3 = 0

7 0
3 years ago
I serve a volleyball at a 730 angle with the horizontal, and an initial speed of 5.6 feet per second. What is the component form
noname [10]
You would split out the velocity into x and y components.
X component: 5.6cos(73)= 1.637i
Y component: 5.6sin(73)= 5.355j

Therefore velocity in its component form is 1.637i + 5.355j ft/s
4 0
3 years ago
Read 2 more answers
What the result of √[(-2a)^ 2]
Tanya [424]
If you take the square root of a number squared number then they cancel each other out and the number stays the same i.e. √[(4)^2] would equal 4.

In this problem the square root and numbered squared cancel out to leave the problem as -2a.

The solution of this problem is -2a
3 0
4 years ago
Sinθ/cosθtanθ=1<br>how is this identity true?​
Yakvenalex [24]

Answer:

This is actually not an identity.

7 0
2 years ago
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