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True [87]
3 years ago
9

A mile is equal to 5280 feet.if the highway department places a reflector every 25 feet how many reflectors will there be in 1 m

ile of highway
Mathematics
2 answers:
murzikaleks [220]3 years ago
8 0
5280/25, ignoring the remainder, equals 211. That's the answer
Tasya [4]3 years ago
6 0

Answer:there will be 211 reflectors on 1 mile of highway

Step-by-step explanation:

A mile is equal to 5280 feet. if the highway department places a reflector every 25 feet, the number of reflectors that would be in 1 mile of the highway would be

Total number of feets / 25. It becomes. 5280/25 = 211.2 reflectors. Approximating 211.2, it becomes 211 reflectors.

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Given the following exponential function, what is the initial amount y 60(1.71)^x?
Aleks [24]

Answer:

60

Step-by-step explanation:

The initial y value can be found by setting x to 0. Anything to the power of 0 is 1, so 1.71^x when x is 0 is just 1. 60*1=60, which is the initial y value. Hope this helps!

8 0
3 years ago
2. Tristan wants to go bowling. He wants to spend no more than $25. It costs $3.00 to rent shoes and $4.50 for each game. What i
liubo4ka [24]

Answer:

3 + 4.50g \leq 25

g\leq 4

Step-by-step explanation:

25 - 3 is 22. 22 divided by 4.50 is a decimal. But it rounds down to 4. So the most amount of games Tristan can play is 4.

Hope it helps!

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3 years ago
The quarterly returns for a group of 6161 mutual funds are well modeled by a Normal model with a mean of 6.16.1​% and a standard
Shtirlitz [24]

Answer:

a) The cut off value of the highest 50% is 6.16%.

b) The cut off value of the highest 16% is 8.8%.

c) The cut off value of the lowest 2.5% is 0.7%.

d) The cut off values of the middle 68% is 3.4% for the lower bound and 8.8% for the higher bound.

Step-by-step explanation:

The 68–95–99.7 rule is an empirical rule to remember the percentage of values that lie within a band around the mean in a normal distribution with a width of two, four and six standard deviations respectively.

a) Cut off value of the highest 50%

It corresponds to the half that has the higher returns, which are the ones that are above the mean (0 standard deviation). The cut off value in this case is the mean x=6.16%.

b) Cut off value of the highest 16%

In this case, we use the 68 rule-value, which means that 68% of the values lies within a band around the mean with a width of two standard deviations.

The percentage that lies out of this band is 100%-68%=32%, of which 16% lies above the band (the highest 16%) and 16% lies below the band.

We can estimate, according to this rule, that the highest 16% are above the cutoff value X of μ+1σ:

X=\mu+\sigma=6.1%+2.7%=8.8%

The cut off value of the highest 16% is 8.8%.

c) Cut off of the lowest 2.5%

In this case, we use the 95 rule.

The lowest 2.5% lies below two standards deviation less of the mean

X=\mu-2*\sigma=6.1%-2*2.7%=0.7%

The cut off value of the lowest 2.5% is 0.7%.

d) Cut off of the middle 68%

In this case we calculate the band within one standard deviation.

X_{low}=\mu-\sigma=6.1%-2.7%=3.4%\\\\X_{high}=\mu+\sigma=6.1%+2.7%=8.8%

The cut off values of the middle 68% is 3.4% for the lower bound and 8.8% for the higher bound.

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3 years ago
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faltersainse [42]

Answer:

A

Step-by-step explanation:

Id say A Im sorry If im wrong though, this is what I would put

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