Answer:
LXXXVII
Step-by-step explanation:
L=50 X=10 V=5 I=1
So basically you need to figure out what adds up to the 87. so use L, or 50. now XXX=30. so now you have 80 so we still have 7 left over, so we can write 7 I's or a 5, (V) and two I's. We should use the V and the I. So we take one V, or 5. and two I's which together is 7. which leads us too LXXXVII. also always remember to have the biggest number first, in this case the L (50).
Answer:
B
Step-by-step explanation:
The most reasonable one is B because its 7 for side B and the rest for B are either bigger or equal to the given number
"Assuming a fair coin<span> and a fair 6-sided </span>die<span>. </span>Coin<span> has 2 sides with </span>equal probability<span>, 50% each. </span>Die<span> has 6 sides with </span>equal probability<span>, 1/6 odds </span>for<span> each side. ... The</span>probability of getting heads<span> is 1/2, and the </span>probability of getting<span> 5 or 6 is 1/3, and so you simply multiply 1/2 x 1/3, which is 1/6."</span>
4y ≥ 3x + 2
Plugging in the values in the options, then the required values are when x = 6 and y = 5, then
4(5) ≥ 3(6) + 2
20 ≥ 18 + 2
20 ≥ 20