d - 3 = (-8)
+3 +3
d = -5
⭐ Please consider brainliest! ⭐
✉️ If any further questions, inbox me! ✉️
Answer:
y = 3
Step-by-step explanation:
-7 = -4y + 5
Subtract 5 from both sides to isolate variable y:
-7 - 5 = -4y + 5 - 5
-12 = -4y + 0
-12 = -4y
Divide both sides by -4 to isolate variable y:
-12 ÷ -4 = -4y ÷ -4
(Negative ÷ Negative = Positive)
3 = 1y
3 = y
Check your work:
-7 = -4(3) + 5
Use PEMDAS:
-7 = -12 + 5
-7 = -7
Correct!
Answer:
500
Step-By-Step Explanation:
200/50 = 4
4 * 17 = 68
68 / 2 = 34
34 x 5 = 170
170 / 17 = 10
10 x 50 = 500
It’s D I also trust the other guy
Answer: Option A: 8.04% compounded daily
<u>Step-by-step explanation:</u>
![A = P\bigg(1+\dfrac{r}{n}\bigg)^{nt}\qquad where\\\\\bullet A = \text{accrued amount (principal plus interest earned)}\\\bullet P = \text{principal (amount invested)}\\\bullet r = \text{rate (in decimal form)}\\\bullet n=\text{number of times compounded in one year}\\\bullet t=\text{time (number of years)}\\\\\\Option\ A:\\A = \text{unknown}\\P=3000\\r=8.04\%\rightarrow 0.0804\\n=\text{daily}\rightarrow 365\\t=10\\\\A=3000\bigg(1+\dfrac{0.0804}{365}\bigg)^{365\times 10}\\\\.\ =\$ 6,702.79](https://tex.z-dn.net/?f=A%20%3D%20P%5Cbigg%281%2B%5Cdfrac%7Br%7D%7Bn%7D%5Cbigg%29%5E%7Bnt%7D%5Cqquad%20where%5C%5C%5C%5C%5Cbullet%20A%20%3D%20%5Ctext%7Baccrued%20amount%20%28principal%20plus%20interest%20earned%29%7D%5C%5C%5Cbullet%20P%20%3D%20%5Ctext%7Bprincipal%20%28amount%20invested%29%7D%5C%5C%5Cbullet%20r%20%3D%20%5Ctext%7Brate%20%28in%20decimal%20form%29%7D%5C%5C%5Cbullet%20n%3D%5Ctext%7Bnumber%20of%20times%20compounded%20in%20one%20year%7D%5C%5C%5Cbullet%20t%3D%5Ctext%7Btime%20%28number%20of%20years%29%7D%5C%5C%5C%5C%5C%5COption%5C%20A%3A%5C%5CA%20%3D%20%5Ctext%7Bunknown%7D%5C%5CP%3D3000%5C%5Cr%3D8.04%5C%25%5Crightarrow%200.0804%5C%5Cn%3D%5Ctext%7Bdaily%7D%5Crightarrow%20365%5C%5Ct%3D10%5C%5C%5C%5CA%3D3000%5Cbigg%281%2B%5Cdfrac%7B0.0804%7D%7B365%7D%5Cbigg%29%5E%7B365%5Ctimes%2010%7D%5C%5C%5C%5C.%5C%20%3D%5C%24%206%2C702.79)
![Option\ B:\\A = \text{unknown}\\P=3000\\r=8.1\%\rightarrow 0.081\\n=\text{quarterly}\rightarrow 4\\t=10\\\\A=3000\bigg(1+\dfrac{0.081}{4}\bigg)^{4\times 10}\\\\.\ =\$ 6,689.37](https://tex.z-dn.net/?f=Option%5C%20B%3A%5C%5CA%20%3D%20%5Ctext%7Bunknown%7D%5C%5CP%3D3000%5C%5Cr%3D8.1%5C%25%5Crightarrow%200.081%5C%5Cn%3D%5Ctext%7Bquarterly%7D%5Crightarrow%204%5C%5Ct%3D10%5C%5C%5C%5CA%3D3000%5Cbigg%281%2B%5Cdfrac%7B0.081%7D%7B4%7D%5Cbigg%29%5E%7B4%5Ctimes%2010%7D%5C%5C%5C%5C.%5C%20%3D%5C%24%206%2C689.37)
Option A results in the greater amount of money.