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3 years ago

5

How to divide 44 and 4340

1 answer:

Rama09 [41]3 years ago

6 0

Answer:

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3 years ago

Given sec(theta)= 5... find cot(90-theta)

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$\sec(\theta)=\frac{1}{\cos(\theta)}
\\
\\\cos(\theta)=\frac{1}{\sec(\theta)}=\frac{1}{5}
\\
\\ \sin^2\theta+\cos^2\theta=1
\\
\\\sin\theta= \sqrt{1-\cos^2\theta}= \sqrt{1-( \frac{1}{5})^2 } = \sqrt{1- \frac{1}{25} } = \sqrt{ \frac{25}{25} -\frac{1}{25} }=\frac { \sqrt{24}}{5} 
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\\ \cot(90^o-\theta)=\tan{\theta}= \frac{\sin\theta}{\cos\theta} = \frac{\frac { \sqrt{24}}{5} }{ \frac{1}{5} } = \sqrt{24} = \sqrt{4\times6}=2 \sqrt{6} 
\\
$

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3 years ago