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vaieri [72.5K]
3 years ago
8

Which car have traveled the farthest

Mathematics
1 answer:
Alona [7]3 years ago
4 0
Can u give me some answers I could pick from
You might be interested in
How can I find c in a=3 b=4
Dahasolnce [82]
A^2+b^2= c^2
3^2+4^2=c^2
9+16=c^2
25=c^2
5=c
8 0
3 years ago
Write 770000 and round it to the nerest lakh​
KATRIN_1 [288]

Answer:

8 lakhs = 8,00,000

Step-by-step explanation:

770000

=> 7,70,000

=> 7.7 lakhs

7.7 lakh rounded to the nearest lakh = 8 lakhs and it is Rounded Up

Hope it helps :)

7 0
2 years ago
How do you change a battery in a car
Nutka1998 [239]

Answer:

Simple

Step-by-step explanation:

Remove cables from battery terminals. ...

Remove the screws or fasteners holding the battery in place; then Remove the Battery. ...

Inspect the tray the old battery was resting on. ...

Position your new car battery on the tray. ...

Replace the screws/fasteners to the new battery to secure it in place.

Step 6. Reconnect your battery cables in the reverse order in which you took them off

4 0
2 years ago
If x+1/x = 5 find the value of x^3 +1/x^3. pls solve​
Korolek [52]

Answer:

1) solve x+1/x = 5

\frac{x + 1}{x}  = 5

x + 1 = 5x

x - 5x =  - 1

- 4x =  - 1

x =  \frac{ -1}{ - 4}

x =  \frac{1}{4}

2) solve x³+1/x³

x {}^{3}  +  \frac{1}{x {}^{3} }

substitute x = 1/4 into the expression

( \frac{1}{4} ) {}^{3}  +  \frac{1}{( \frac{1}{4}) {}^{3}  }

\frac{1}{64}  +  \frac{1}{ \frac{1}{64} }

\frac{1}{64}  +  \frac{64 \times 1}{1}

\frac{1}{64}   + 64

\frac{4097}{64}  \: or \: 64.02

5 0
3 years ago
Let n be a natural number. Show that 3 | n3 −n
Vladimir [108]
Let n=1. Then n^3-n=1^3-1=0. By convention, every non-zero integer n divides 0, so 3\vert n^3-n.

Suppose this relation holds for n=k, i.e. 3\vert k^3-k. We then hope to show it must also hold for n=k+1.

You have

(k+1)^3-(k+1)=(k^3+3k^2+3k+1)-(k+1)=(k^3-k)+3(k^2+k)

We assumed that 3\vert k^3-k, and it's clear that 3\vert 3(k^2+k) because 3(k^2+k) is a multiple of 3. This means the remainder upon divides (k+1)^3-(k+1) must be 0, and therefore the relation holds for n=k+1. This proves the statement.
4 0
3 years ago
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