The diagram can be redrawn as,
The value of x and y can be determined as,
![\begin{gathered} \tan C=\frac{AB}{BC} \\ \tan 45^{\circ}=\frac{x}{7\sqrt[]{2}} \\ x=7\sqrt[]{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctan%20C%3D%5Cfrac%7BAB%7D%7BBC%7D%20%5C%5C%20%5Ctan%2045%5E%7B%5Ccirc%7D%3D%5Cfrac%7Bx%7D%7B7%5Csqrt%5B%5D%7B2%7D%7D%20%5C%5C%20x%3D7%5Csqrt%5B%5D%7B2%7D%20%5Cend%7Bgathered%7D)
![\begin{gathered} \cos C=\frac{BC}{AC} \\ \cos 45^{\circ}=\frac{7\sqrt[]{2}}{y} \\ y=14 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ccos%20C%3D%5Cfrac%7BBC%7D%7BAC%7D%20%5C%5C%20%5Ccos%2045%5E%7B%5Ccirc%7D%3D%5Cfrac%7B7%5Csqrt%5B%5D%7B2%7D%7D%7By%7D%20%5C%5C%20y%3D14%20%5Cend%7Bgathered%7D)
Thus, option (D) is the correct solution.
Answer:
The number of tables were used that day at lunch is 23 tables.
Step-by-step explanation:
Given as :
The total number of students in the Polk school = 203
On one day the number of students absent = 19
So, The number of student present on that day = Total student - absent students
I.e The number of student present on that day = 203 - 19 = 184
The number of students sit on each table = 8
Let The number of tables were used that day at lunch = n
<u>So, According to question</u>
The number of tables were used that day at lunch = 
I.e n = 
∴ n = 23 tables
So, The number of tables were used that day at lunch = n = 23 tables
Hence, The number of tables were used that day at lunch is 23 tables. Answer
Answer:That is incorrect. 12.8 is greater than 12.68 because .8 is greater than .68
Step-by-step explanation: Since “68” has been placed after the decimal, it is actually “.68” which is less than 1. From here, you have to figure out if .8 or .68 is closer to the number 1 and since .8 is closer, point 12.8 is greater than 12.68
The answer is 1/6 because 2/3-1/2 the command denominator is 6 so 2 goes in six 3 times then you do 3×1 =3 so you got 3/6 then you do 3 goes in 6 2 times then you do 2×2=4 and 4-3=1 so you get 1/6
Answer:
- <u>They can catch up with the bus at 10:40 am.</u>
Explanation:
1. Set the time when Liana and her mother can leave (8:40 am) as t₀ = 0; thus the time of driving for them will be t.
2. The average speed at whic Liana's mother drive: 60 miles/hour
3. Thus, the distance they will have driven will be:
- distance = average speed × time = 60t
4. The time the bus left was 8:00 am, which is 40 minutes before Liana and her mom can leave.
Thus, the time wil have driven when Liana and her mom have driven t hours minutes will be: t + 40 min / 60 min/ hour = t + 2/3
5. The average speed of teh bus is 45 miles / hour
6. The distance the bus will have driven will be:
- distance = average speed × time = 45(t + 2/3)
7. When Liana and her mother catch up with the bus, the distances driven by both of them are equal:
Thus, Liana and her mom can catch up with the bus after 2 hours, since 8:40 am; this is, 10:40 am.
