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2 years ago

Find the area of the shape shown below

Mathematics

1 answer:

ra1l [238]2 years ago

3 0

Answer:

18 MARK AS BRAINLIEST OR ELSE!!!!

Step-by-step explanation:

area = 1/2h(sum of bases)

area = 1/2x3(3+9)

area = 1/2 of 36

area = 18

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Find the product. (-5a ^2)^3·a ^5 A)-15a10 B)-125a11 C)15a6 D)-125a10

Ber [7]

Answer:

B) -125a^11

Step-by-step explanation:

(-5a^2)^3·a^5 = (-5)^3·a^6·a^5

= (-5)^3·a^(2·3)·a^5

= (-5)^3·a^6·a^5

= -125·a^(6+5)

= -125·a^11 . . . . matches choice B

_____

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

(a^b)^c = a^(bc)

5 0

2 years ago

Read 2 more answers

Answer quickly please <3

sertanlavr [38]

Answer:

x is greater than -5

Step-by-step explanation:

3 0

3 years ago

Nathan is going to invest in an account paying an interest rate of 4.8% compounded continuously. How much would Nathan need to i

Elena-2011 [213]

Answer:

you would just 4.8 x how many years

Step-by-step explanation:

4 0

3 years ago

Determine if the coordinate (6, 8) lies on the circle x^2 + y^2 = 100.

SVEN [57.7K]

Answer:

x² + y² = 100

6² + 8² = 100

36 + 64 = 100

100 = 100

Because this is a true statement, the answer is yes, it does lie on the circle.

3 0

2 years ago

An assembly consists of two mechanical components. Suppose that the probabilities that the first and second components meet spec

harkovskaia [24]

Answer:

P(X = 0) = 0.0208, P(X = 1) = 0.2484, P(X = 2) = 0.7308

Step-by-step explanation:

Let's define the following events

A: the first component meet specification

B: the second component meet specification

P(A) = 0.87

P(B) = 0.84

Let X be the random variable that represents the number of components in the assembly that meet specifications. Because there are only two mechanical components in the assembly, X can only take the values 0, 1, 2.

P(X = 0) = P(the first component does not meet specification and the second component does not meet specification) =

$P(A^{c}\cap B^{c}) = P(A^{c})P(B^{c})$ (because of independence)

= (0.13)(0.16) = 0.0208

P(X = 1) = P(only one component meet specification) = P[(the first component meet specification and the second component does not meet specification) or (the first component does not meet specification and the second component meet specification)] =

$P[(A\cap B^{c})\cup (A^{c}\cap B)] = P(A\cap B^{c}) + P(A^{c}\cap B)=$ (because sets are mutually exclusive)

$P(A)P(B^{c}) + P(A^{c})P(B)=$ (because of independence)

= (0.87)(0.16) + (0.13)(0.84) = 0.2484

P(X = 2) = P(both components meet specifications) =

$P(A\cap B) = P(A)P(B)$ (because of independence)

= (0.87)(0.84)

= 0.7308

8 0

3 years ago